International Journal of Heat and Technology
Vol. 39, No. 5, October, 2021, pp. 1430-1442
Journal homepage: http://iieta.org/journals/ijht
On Some Thermoelastic Problem of a Nonhomogeneous Long Pipe
Roman Kulchytsky-Zhyhailo1, Stanisław J. Matysiak2, Dariusz M. Perkowski1*
Department of Mechanics and Applied Computer Science, Faculty of Mechanical Engineering, Białystok University of
Technology, 45C Wiejska Str., Białystok 15-351, Poland
2
Institute of Hydrogeology and Engineering Geology, Faculty of Geology, University of Warsaw, Al. Żwirki i Wigury 93,
Warsaw 02-089, Poland
1
Corresponding Author Email: d.perkowski@pb.edu.pl
https://doi.org/10.18280/ijht.390504
ABSTRACT
Received: 26 July 2021
Accepted: 22 September 2021
The paper deals with the thermoelastic problem of a multilayered pipe subjected to normal
loadings on its inner surface and temperature differences on its internal and external
surfaces. Two types of nonhomogeneous pipe materials of pipe are considered: (1) a ringlayered composite composed of two repeated thermoelastic solids with varying thickness
and (2) a functionally graded ring layer. The ring-layered pipe with periodic structure is
investigated by using the homogenized model with microlocal parameters. A
homogenization approach is proposed for the modelling of the FGM pipe. The analysis of
obtained circumferential, radial and axial stress is presented in the form of figures and
discussed in detail. It was shown that the proposed approach to the homogenization allows
us to correctly calculate the averaged characteristics in the representative cell (the macrocharacteristics) and also the characteristics dependent on the choice of the component in
the representative cell (the micro-characteristics) for both microperiodic composites and
functionally graded materials.
Keywords:
temperature, displacement, thermal stress,
composite material, functionally graded
material, nonhomogeneous pipe
The optimal values of the circumferential stress component are
shown to correspond to the shear modulus given in the form of
a linear function.
The basis for the analysis of thermoelastic temperature,
temperature and stress is the prior determination of a solution
to the problem of heat conduction for a solid with functionally
graded properties. The papers [13-15] are devoted to the
axisymmetrical heat condition problems in the case of the
assumption that the heat conductivity coefficient is described
by an exponential or power functions of the radius.
The functional gradation of the materials leads to partial
differential equations with variable coefficients. Solving such
problems within the classical approach is rather difficult. One
of the simplification methods relies on approximate averaging
techniques. For example, in the paper [16], the approach
related to the replacement of bodies with functionally graded
properties by a heterogeneous solids consisting of a package
of layers, in which the thermomechanical properties of
sublayers are averaged and constants, is applied. However, in
this case the solution of an approximate system of equations
should fulfill the conditions of perfect thermal and mechanical
contact on the interfaces and the assumed boundary conditions.
Another approach to the problems of periodic body heat
condition is a use of the homogenized model with microlocal
parameters [17-19] or the application of the tolerance model
[20, 21]. The homogenized model with microlocal parameters
is widely used to solve a number of problems for the composite
bodies with periodic structure [22-31].
A wide review of the literature on the thermomechanics of
functionally graded bodies can be found by Noda [32]. For
example, in the paper [33], an exact solution is presented to
the three-dimensional thermoelastic problem of a circular plate
1. INTRODUCTION
The development of engineering structures and their
applications in various industries require modern materials.
The results in the formation of these solids are to be applicable
in specific engineering branches. One of such materials is
functionally graded materials (FGM). The FGM are
characterized by the continuous or step changing mechanical,
thermal and chemical properties [1]. Taking into account the
chemical and physical properties, changes in the FGM
materials can be divided into two groups [2]: a change in
chemical composition gradation, a change in the structure or a
change in porosity. Functionally graded materials are used as
thermal barrier coatings [3] or as wear reduction layers.
A comprehensive review of various ceramic materials
applied as thermal barriers is presented by Lee et al. [4]. The
thermomechanical properties of the FGM materials used for
thermal barriers are discussed by Wang et al. [5], and Chen
and Tong [6].
In the literature, many works deal with stress states under
the influence of temperature fields for various types of
considered bodies, e.g., an empty cylinder [7], plates [8] or a
sphere [9, 10]. For the analysis of such problems, the methods
used methods should allow to determine distributions of
temperature, displacement, heat flux and stress with
sufficiently high accuracy.
The three-dimensional problem of thermomechanical
deformation of a freely supported rectangular plate subjected
to a sudden temperature pulse is analyzed by Vel and Batra
[11]. The material of the plate is assumed to be characterized
by thermomechanical properties in the form of power-type
functions. A cylinder with FGM material is considered [12].
1430
subjected to thermal and mechanical loadings. It was assumed
there that, apart from the Poisson’s ratio, all the thermal and
mechanical material are described by exponential functions of
the depth of the boundary surface.
The paper [34] presents an approach to solving two or threedimensional thermoelasticity problems for materials with
functionally graded properties using the boundary element
method combined with analytical methods. The authors
showed that the proposed manner of solving is more effective
than the finite element method.
In this paper, the stress field in the nonhomogeneous pipe
subjected to the normal pressures on the inner surface and to a
temperature difference on the inner and outer surfaces is
investigated. It is assumed that the external pipe surface is
unloaded. The pipe is composed of materials with functionally
gradation, in which the thermomechanical properties are
described by continuous functions of the radius, as well as with
the ring layered structures. In the last case, the ideal
thermomechanical contact conditions on the interfaces are
considered. As a special case, the periodic structure of the pipe
material is considered. Certain novel approach to the
homogenization with microlocal parameters to modeling of
thermoelastic problem of FGM pipe is proposed.
Figure 1. The scheme of considered problem
Considering the nonhomogeneous pipe characterized by the
mechanical and thermal properties, the fields of displacement,
temperature and stress in its i-th, i=1,…,n components will be
described using the following state functions: the radial
(𝑖)
(𝑖)
displacement 𝑢(𝑖) , the radial 𝜎𝑟𝑟 , the circumferential 𝜎𝜑𝜑 and
(𝑖)
the axial 𝜎𝑧𝑧 components of stress tensor 𝜎 (𝑖) and the
temperature 𝑇 (𝑖) . The introduced functions can be calculated
by solving the following system of differential equations:
2. FORMULATION OF THE PROBLEM
The state of stress in a long nonhomogeneous pipe with the
radiuses: internal R0 and external R1 is investigated. The stress
field is caused by normal pressures p0 applied to the inner pipe
surface and by a temperature difference θ0 in its inner and
outer surfaces (see Figure 1). The external pipe surface is
unloaded. The considerations will be led using the
dimensionless cylindrical coordinates (r, φ, z) related to the
dimension R1. It is assumed that the considered problem is
axially symmetrical and its solution is independent of the
coordinate z in the axial direction. Similarly, as in the classical
homogeneous pipe problem [35], it will be assumed that the
axial displacement is equal to zero everywhere, but the axial
stress is non-zero. In the case of the pipe with unloaded
boundaries, the boundary conditions at the ends of the pipe are
neglected. Additionally, applying uniform axial stress and
taking its value in such manner that the total resultant force in
the axial direction is zero, we obtain on both pipe ends the self
-balanced distribution of axial pressures. According to the
Saint-Venant principle, it causes only local effects near the end
of the pipe ends [29]. Since imposing additional uniform axial
stress does not cause changes in the distribution of radial and
circumferential stress, its influence in the framework of this
article will be omitted.
The nonhomogeneous pipe in its cross section is composed
of n=2m ring layers (see Figure 1), where m is the number of
representative cells. The representative cell with
dimensionless thickness δ=(1-r0)/m, (r0=R0/R1) contains two
homogeneous ring layers with Young modules E1, E2, Poisson
coefficients ν1, ν2, the coefficients of linear thermal expansion
α1, α2, the thermal conductivity coefficients K1, K2, and
dimensionless thickness δ1=ηδ, δ2=(1-η)δ, where the
parameter η(0,1) describes the contents of the first kind of
material and can vary along the thickness of the pipe. The pipe
components are located in the regions 𝑟𝑖−1 < 𝑟 < 𝑟𝑖 , 𝑖 =
1,2, . . . , 𝑛 respectively, where 𝑟2𝑗 = 𝑟0 + 𝑗𝛿, 𝑟2𝑗−1 = 𝑟2𝑗 −
𝛿2 , 𝑗 = 1,2, . . . , 𝑚. The ideal thermal and mechanical contact
between the pipe components is taken into account.
d dT (i )
r
dr dr
= 0
(1a)
d 1 d
1 + (i ) (i ) (i )
i
T = 0;
ru ( ) −
dr r dr
1 − ( i )
(1b)
i
i
rr(i )
1 − ( ) du ( )
( i ) u ( i ) 1 + ( i ) ( i ) ( i )
=
+
−
T
i
i
i
i
2 ( ) 1 − 2 ( ) dr 1 − 2 ( ) r 1 − ( )
(1c)
(
(i )
2 ( )
i
=
)
(i ) du (i ) 1 − (i ) u (i ) 1 + (i ) (i ) (i )
T
+
−
i
i
i
1 − 2 ( ) dr 1 − 2 ( ) r 1 − ( )
(
)
i
i
i
(i )
− E ( ) ( )T ( ) ;
zz(i ) = (i ) rr(i ) +
r ( ri −1 , ri ) , i = 1, 2,..., n
(1d)
(1e)
and satisfying the boundary conditions on the internal and
external surfaces of the pipe:
rr(1) ( r0 ) = − p0 , rr( n) ( rn ) = 0
(2a)
T (1) ( r0 ) = 0 , T ( n) ( rn ) = 0
(2b)
and the conditions of ideal mechanical and thermal contact
between the pipe components
u ( ) ( ri − 0 ) = u (
i
i +1)
rr ( ri − 0 ) = rr
(i )
( i +1)
( ri + 0 ) ,
( ri + 0 ) ,
i = 1, 2,..., n − 1
1431
(3a)
T ( ) ( ri − 0 ) = T (
i
K
(i )
i +1)
( ri + 0 ) ,
dT ( )
dT (
( ri − 0 ) = K (i +1)
dr
dr
i = 1, 2,..., n − 1,
i +1)
i
( ri + 0 ) ,
= 0, r ( r0 ,1)
•
(7c)
(1 − ) 2 ( 32 + 22 )( 1 + 21 )
+
(1 − )( 1 + 21 ) + ( 2 + 22 )
1 ( 31 + 21 )( 2 + 22 )
+
;
(1 − )( 1 + 21 ) + ( 2 + 22 )
(7d)
+
1 ( 31 + 2 1 ) 2
(1 − )( 1 + 21 ) + ( 2 + 22 )
( ( 3
1
1
( j)
= Dj
duhom
u
+ E j hom − Fj Thom , j = 1, 2;
dr
r
(
)
( j)
zz( j ) = G j rr( j ) +
− H j Thom , j = 1, 2
( 1 + 21 )( 2 + 22 )
(1 − )( 1 + 21 ) + ( 2 + 22 )
;
4 j ( j + j ) + j B
j A1
; Ej =
, j = 1, 2
j + 2 j
j + 2 j
2 j ( 3 j + 2 j ) j + j 1
j + 2 j
j
2 ( j + j )
j =
(6a)
, Hj =
, j = 1, 2
j j ( 3 j + 2 j )
j + j
, j = 1, 2
(7f)
(7g)
(7h)
E j j
(1 + )(1 − 2 )
j
; j =
Ej
2 (1 + j )
(8)
It should be emphasized that the proposed homogenization
method allows us to directly calculate the stress component in
each component of the periodicity cell. It is especially
important in the case of the circumferential and axial stress
that receive jumps on the interfaces between the pipe
components. The radial stress is continuous at the interfaces
and they are the same, as follows from the Eq. (6a), in both
components of the periodicity cell, and they are equal to the
averaged radial stress within the periodicity cell. It is easy to
verify, that
(6b)
(6c)
In the Eqns. (4)-(6) the following notation is introduced:
uhom , rrhom and Thom denote the state functions that describe
radial displacement, radial stress and temperature, respectively,
(𝑖)
(𝑖)
(𝑖)
which are averaged within the periodicity cell; 𝜎𝑟𝑟 , 𝜎𝜑𝜑 , 𝜎𝑧𝑧
are the radial, circumferential and axial stress in the j-th
component of the periodicity cell;
A1 =
(7e)
+ 21 ) + (1 − ) 2 ( 32 + 2 2 ) )
j
duhom
u
+ B hom − 1Thom
dr
r
+
The constants λj, μj in Eqns. (7) are Lame constants of the jth, j=1,2, component of the periodicity cell, and
The stress state in the homogenized pipe can be calculated
using the following equations:
rr(1) = rr( 2) = rrhom = A1
+
(1 − )( 1 + 21 ) + ( 2 + 22 )
Fj =
Gj =
(5b)
(1 − )( 1 + 21 ) + ( 2 + 22 )
+2 ( 2 + (1 − ) 1 )
the boundary conditions:
Thom ( r0 ) = 0 , Thom (1) = 0.
(1 − ) 2 ( 32 + 22 ) 1
2 =
(4b)
(5a)
(7b)
1 =
(4a)
rrhom ( r0 ) = − p0 , rrhom (1) = 0
;
(1 − ) 2 ( 1 + 21 ) + 1 ( 2 + 22 )
(1 − )( 1 + 21 ) + ( 2 + 22 )
B=
Dj =
d 2 uhom A1 duhom
u
A1
+
− A2 hom
=
2
r dr
dr
r2
dT
( − 2 )
Thom , r ( r0 ,1) ;
= 1 hom + 1
dr
r
(1 − )( 1 + 21 ) + ( 2 + 22 )
(3b)
where, (2j-1) = 1, (2j) = 2, (2j-1) = 1, (2j) = 2, K(2j-1) = K1,
K(2j) = K2, µ(2j-1) = µ1, µ(2j) = µ2, E(2j-1) = E1, E(2j) = E2, j = 1, 2, ...,
m are the Poisson’s coefficients, the coefficients of linear
thermal expansion, the coefficients of heat conductivity, the
Kirchhoff coefficients, and Young modulus of the subsequent
pipe components.
Case 1
In the first place, the case in which the parameter η is
constant along the pipe thickness will be investigated. The
solution of the problem for multilayered pipe with periodic
structure will be compared with the solution of the problem of
the homogeneous pipe, in which the mechanical and thermal
properties will be determined by using the method of
homogenization with microlocal parameters [24]. The
received boundary value problem has the form:
• the equations:
d dThom
r
dr dr
4 (1 − )( 1 − 2 )( 1 + 1 − 2 − 2 )
A2 = A1 +
B = D1 + (1 − ) D2 ,
A2 = E1 + (1 − ) E2 ,
(9)
2 = F1 + (1 − ) F2 .
Therefore, the averaged circumferential stress is given by
(7a)
1432
(1)
( 2)
hom
=
+ (1 − )
=
=B
duhom
u
+ A2 hom − 2Thom
dr
r
s2 n −1 + s2 n = 0.
(13d)
(10)
Substituting the solution of the system of Eqns. (13) into
Eqns. (12) the distribution of stress in the nonhomogeneous
pipe is obtained.
In the second approach based on the homogenized model
the general solution of homogeneous equivalent of Eq. (4b)
has the form:
The analogous dependence takes place in the case of
averaged axial stress.
Because the considered boundary problems are linear, the
state functions in both approaches can be presented in the form
of a sum of two components. The first component describes
the solution to the problem of the elasticity theory related to
the loading of the internal pipe surface with normal pressure
p0. This solution is constructed under assumption that the
temperature is equal to zero. The second component of the
solution is associated with the calculation of thermal stress
caused by the difference in temperature difference on the inner
and outer pipe. It enables an independent analysis of each of
the mentioned problems.
(1)
( 2) −
uhom ( r ) = shom
r + shom
r , r0 r 1
(14)
= A2 A1
(15)
where,
The stress components in the j-th component of the
periodicity cell are equal to:
(1) −1
rr(1) = rr( 2) = rrhom = ( A1 + B ) shom
r +
3. THE CALCULATIONS OF THE SOLUTION OF
ELASTICITY PROBLEM
( ) − −1
− ( A1 − B ) shom
r ;
2
In the first direct approach, we are integrating the
homogeneous equivalent to Eq. (1b). Their general solutions
can be written in the form:
( j)
(1) −1
= ( D j + E j ) shom
r +
( ) − −1
− ( D j − E j ) shom
r , j = 1, 2;
2
(
)
u (i ) ( r ) = 1 − (i ) s2i −1r − s2i r −1 ,
ri −1 r ri , i = 1, 2,..., n.
(
(11)
The radial displacement u(i) generates the stress tensor,
which has nonzero components:
( 2 ( ) )
i
−1
rr(i ) ( r ) = s2i −1 + s2i r −2 ,
ri −1 r ri , i = 1, 2,..., n;
( 2 ( ) )
i
−1
(i )
( r ) = s2i −1 − s2i r −2 ,
ri −1 r ri , i = 1, 2,..., n;
(
)
(i )
zz(i ) = (i ) rr(i ) +
= 4 (i ) (i ) s2i −1 ,
ri −1 r ri , i = 1, 2,..., n.
)
( j)
zz( j ) = G j rr( j ) +
, j = 1, 2
(16a)
(16b)
(16c)
From the boundary conditions (5a) the values of constants
(1)
(2)
𝑠ℎ𝑜𝑚 and 𝑠ℎ𝑜𝑚 are obtained:
()
=
shom
1
(12a)
( 2)
=
shom
(12b)
− p0 r0
( A1 + B ) ( r0
− p0 r0
( A1 − B ) ( r0
− r0− )
,
− r0− )
.
(17)
By plugging Eqns. (17) into (16), the radial, circumferential,
and axial stress in both components of the periodicity cell are
determined.
(12c)
4. THE CALCULATIONS OF THERMAL STRESS
The unknown parameters 𝑠𝑖 , 𝑖 = 1,2, . . . ,2𝑛 in the Eqns. (11)
and (12) are calculated using the boundary conditions (2a) and
(3a). The following system of equations is obtained:
s1 +
p
s2
= − 0(1)
2
r0
2
(1 − 2 ( ) ) s
i
r−
2i −1 i
(
− 1 − 2
( i +1)
s2i −1 +
)
s2i
+
ri
s
s2i +1ri + 2i + 2 = 0, i = 1, 2,..., n − 1;
ri
s2i (i +1)
(i +1)
s
s2i + 2 = 0,
−
−
2i +1
ri 2
(i )
(i ) ri 2
The general solutions of Eq. (1) described by the
nonhomogeneous pipe have the form:
T ( ) ( r ) 0 = ( ) ( r ) = t2i −1 + t2i ln ( r ri ) ,
i
(13a)
i
ri −1 r ri , i = 1, 2,..., n;
(
)
u ( ) ( r ) = 1 − 2 ( ) s2i −1r −
i
(13b)
1 + ( )
i
−
(13c)
(i ) 0
(i )
i
s2i
+
r
r
1 i (i )
x ( x ) dx,
r r
1 −
ri −1 r ri , i = 1, 2,..., n.
The solutions (18) generate the field of stress.
i = 1, 2,..., n − 1;
1433
(18a)
(18b)
rr(i ) ( r )
2
(i )
= s2i −1 +
1 + ( )
i
+
(i ) 0
(i )
2
1 +
1 −
−
(i )
ri
()
x ( x ) dx,
i
(i ) 0
(i )
1 + (i )
(i )
1
r2
ri =
ri
()
x ( x ) dx +
(19b)
( i ) 0 (i ) ( r ) ,
1 −
ri −1 r ri , i = 1, 2,..., n;
zz(i ) ( r )
2 ( )
i
= 2 ( ) s2i −1 −
i
ri −1
1 + ( )
i
(i ) 0 ( r ) ,
1 − ( )
r ri , i = 1, 2,..., n.
i
t2i −1 − t2i +1 − t2i + 2 ln ( ri ri +1 ) = 0, i = 1, 2,..., n − 1
(20b)
K (i )t2i − K (i +1)t2i + 2 = 0, i = 1, 2,..., n −1
(20c)
t2 n −1 = 0
(20d)
(1 − 2 )
(i )
+
(
(i )
( i ) s2 i
s
+
− s2i +1 +
2
1
i
−
2
(i +1)
(i +1) ri
−
s2 i + 2
= ti , i = 1, 2,..., n − 1;
ri 2
s2n −1 + s2n = 0
(25a)
1 − 2 (1) 2 A1 2 − 1 ( A1 + A2 ) ( 2)
thom +
thom
2
A1 − A2
( A1 − A2 )
(25b)
1t
( )
shom
=
The components of the stress tensor in the j-th component
of the periodicity cell are given by
rr(1) = rr( 2) = rrhom =
( ) −1
( ) − −1
r − ( A1 − B ) shom
r
= ( A1 + B ) shom
+
1
)
s2i + 2
= −ti ri , i = 1, 2,..., n − 1;
ri
(24)
1 − 2 ( 2)
thom
A1 − A2
( )
=
shom
(21a)
s
s2i −1ri − 2i − 1 − 2 (i +1) s2i +1ri +
ri
(23)
where,
Whereas the parameters si, i = 1, 2, ..., 2n in Eqns. (18b) and
(19) will be calculated satisfying the boundary conditions (2a)
and (3a), leading to the system of equations:
s2
= −t0
r02
(22b)
(1)
(1t )
( 2t )
uhom
r ln ( r ) + shom
r , r0 r 1
( r ) = shom
2t
s1 +
ri 2+1 − ri 2
, i = 0,1,..., n − 1
4ri 2
Next, the general solution of Eq. (4b) is constructed. For this
purpose, to the general solution of homogeneous equivalent of
equation of (4b), given in Eq. (14), some special solution
should be added. The special solution has the form:
The unknown parameters si, i = 1, 2, ..., 2n in Eq. (18a) will
be determined from the boundary conditions (2b) and (3b).
The following system of equations is obtained:
(20a)
(22a)
(1)
( 2)
Thom ( r ) = thom
+ thom
ln ( r ) , r0 r 1
(19c)
t1 + t2 ln ( r0 r1 ) = 1
(i +1) 0
By first solving the system of Eqns. (20) and next, the
system (21), the constants ti, si, i = 1, 2, ..., 2n, will be
determined, and after substituting their values into Eqns. (18)
and (19), the state of thermal stress in the considered pipe will
be found.
In the second alternative approach based on the
homogenization method, the Eq. (4a) is integrated. Its general
solution has the following form:
i
r
1 − ( i +1)
1
2t2i +1ri − t2i + 2 ri + ln ( ri ri +1 ) ,
2
i = 0,1,..., n − 1;
(19a)
s
= s2i −1 − 22i +
r
(i )
1 + ( i +1)
ti =
1 −
r
ri −1 r ri , i = 1, 2,..., n;
(i )
(r )
−
1
r2
s2 i
+
r2
2
(1t )
(1t )
( 2t )
+ shom
ln ( r ) + A1 ( shom
( A1 + B ) shom
)+
(21b)
(26a)
( )
+ Bshom
− 1Thom ,
2t
( j)
(1) −1
( 2 ) − −1
= ( D j + E j ) shom
r − ( D j − E j ) shom
r
+
(
)
( )
( )
( )
ln ( r ) + D j shom
+ ( D j + E j ) shom
+ shom
+
1t
(21c)
1t
2t
(26b)
( 2t )
+ E j shom
− FjThom , j = 1, 2,
(
)
( j)
zz( j ) = G j rr( j ) +
− H j Thom , j = 1, 2
(21d)
The boundary conditions (5b) are satisfied, if
where,
1434
(26c)
(1)
( 2)
thom
= 0, thom
=
0
5. RESULT ANALYSIS
(27)
ln ( r0 )
An analysis of the stress state will be derived using the
dimensionless stress. The stress caused by the pressures will
be related to the parameter p0. Although thermal stress is
related to the parameter E**0, where E* = min(E1,E2), * =
max(1,2). The analysis of the received relations shows that
if the mathematical model of the pipe is based on the
homogenization method, then the stress distribution caused by
the pressures depends on five dimensionless parameters: the
ratio between the internal and external radiuses of the pipe r0
= R0/R1, the ratio between the Young modulus of the
periodicity cell E1/E2, the two Poisson coefficients of the
components of the periodicity cell and the parameter η=δ1/δ.
The thermal stress is also dependent on the ratio between the
coefficients of linear thermal expansion 1/2. It can be
emphasized that within the problem framework of the
considered problem the stress does not depend on the ratio
between the coefficients of heat conductions K1/K2. However,
if the pipe is treated as a nonhomogeneous solid, one should
take into account the number of periodicity cells m (or the
number of ring layers n) and also, when performing the
calculations of the thermal stress, the parameter K1/K2.
Whereas, using the boundary conditions (5a), the values of
(1)
(2)
constants 𝑠ℎ𝑜𝑚 and 𝑠ℎ𝑜𝑚 are obtained:
(1)
( 2t )
(1t )
S hom
r0 + S hom
( r0− − r0 )
( 2)
( )
( )
S hom
r0 + S hom
( r0 − r0 )
shom =
( A1 + B ) ( r0
2t
shom =
− r0− )
,
(28)
1t
( A1 − B ) ( r0
− r0− )
,
where,
(
)
( )
( )
( )
( )
Shom
= A1 shom
+ shom
+ Bshom
,
1t
1t
2t
2t
(29)
( )
( )
Shom
= 10 − ( A1 + B ) shom
ln ( r0 ) .
2t
1t
Substituting Eqns. (27) and (28) into (23) and (26), the
radial, circumferential, and axial stress in every ring layer of
the periodicity cell are calculated.
a)
a)
0
0.5
0.6
0.7
r
0
0.8
0.9
1
-0.2
-0.4
0.5
0.6
0.7
0.8
0.9
1
0.8
0.9
1
-0.2
(rrp ) p0
-0.4
-0.6
-0.6
-0.8
-0.8
-1
-1
(rrp ) p0
b)
0
0.5
0.6
0.7
b)
r
0
0.8
0.9
0.5
1
-0.05
-0.05
-0.1
-0.1
Homogeneous
pipe
-0.15
-0.2
0.6
0.7
r
Homogeneous
pipe
-0.15
-0.2
(th )
-0.25
r
rr
E **0
-0.25
(rrth )
E **0
Figure 2. Distribution of radial stress along the pipe thickness; Figure 2a and 2a are related to the stress caused by normal
pressures; Figure 2b and 2b present the stress caused by the difference in temperature; E1/E2 = 10 (or E2/E1 = 10); 2a for m = 10;
2a for m = 20; 2b for m = 20; 2b for m = 40
1435
a)
4
a)
(p ) p0
( p)
p0
4
m=20
m=40
3
3
1th kind layer
1th kind layer
2
2
1
1
Homogeneous pipe
2nd
Homogeneous pipe
kind layer
0
2nd kind layer
0
0.5
0.6
0.7
0.8
0.9
r
0.5
1
0.6
0.7
b)
1.6
1
2nd kind layer
E110
0.8
0.8
Homogeneous pipe
Homogeneous pipe
0
0
0.5
0.6
0.7
0.8
0.9
r 1
1th kind layer
0.5
-0.8
0.6
0.7
0.8
0.9
r 1
1th kind layer
-1.6
-1.6
-2.4
(th )
2nd kind layer
E110
-0.8
r
0.9
b)
1.6
th )
(
0.8
m=20
-2.4
m=40
Figure 3. Distribution of circumferential stress along the pipe thickness; Figure 3a, 3a are connected with the stress caused by
normal pressures; Figure 3b, 3b present the stress caused by difference of temperature; in Figure 3a, 3a it is taken E1/E2 = e; in
Figure 3b, 3b it is taken E2/E1 = e; in Figure 3a, 3b it is assumed m = 20; in Figure 3a, 3b it is assumed m = 40; grey lines and
rhombuses are for e = 5; black lines and rhombuses are for e = 10
In order to decrease the number of parameters and decrease
the range of their changes, the following assumptions are used:
1) The ratio between the internal and external radiuses of
the pipe is 0.5, so r0 = R0/R1 = 0.5;
2) The thickness of each ring layer being the component of
pipe is the same, so = 0.5;
3) The Poisson’s ratios both components of periodicity cell
are the same and 1 = 2 =0.3;
4) One of the pipe components is a thermal insulator. The
applied insulating materials are often characterized by a
greater Young modulus but smaller coefficient of linear
thermal expansion and smaller coefficient of thermal
conductivity. For this reason, the following assumptions, that
E1/E2 = 2/1 = K2/K1 are taken into account;
5) In the aim of an emphasis of possible differences between
the solutions obtained by the two presented approaches, some
relatively large values of the parameter E1/E2 (or E2/E1) are
assumed.
Figure 2 show the distribution of radial stress along the pipe
thickness. Figures 2a and 2a concern the problem, in which
the stress is caused by normal pressures p0. Figures 2b and 2b
present the stress distribution caused by differences in
temperature on the external and internal pipe surfaces. The
continuous lines describe the stress distribution in the pipe
obtained within the framework of the homogenization method.
Radial stress does not depend on the sequence of ring layers
arranged in the periodicity cell. The distribution of radial stress
received within the framework of direct approach depends on
the sequence of ring layers. The relation is described by using
black and grey triangles. The black triangles present the case,
when the first component of periodicity cell is the ring layer
with larger Young modulus, the grey triangles for the first
layer with smaller Young modulus. From Figure 2 it follows
that the values of radial stress for the homogenized model are
located between the adequate values obtained within the direct
approach calculated for the both sequences of insulating ring
layers location in the periodicity cell. The difference between
the locations of black and grey triangles decreases along with
1436
of circumferential stress in the periodicity cell. In Figure 3 the
rhombuses are adequate for the direct approach. If the stress is
calculated in the layers with odd numbers, the adequate
rhombuses are consistent with the continuous line denoted by
1, in the layers with even numbers, with the continuous line
denoted by 2. This means that the continuous lines within the
homogenized model correctly determine the distribution of
stress in the both ring layers in periodicity cell.
As follows from Figure 3, the highest value of
circumferential stress in the elasticity theory problem is taken
on the internal pipe surface, but in the case of thermal stress –
on the external pipe surface. In both cases, it is the greatest
tensile stress. In order to compare the difference calculation of
greatest tensile stress, which is caused by an application of
both proposed approaches, the sequence of ring layers in the
periodicity cell is chosen in such manner, that in the place of
appearance of the greatest circumferential stress there is the
ring layer with greater Young modulus. For this reason, when
calculating the circumferential stress in the problem of
elasticity theory, it is assumed that E1/E2 > 1, and in the case
of thermal stress we assumed that E2/E1 > 1.
an increase of the number of periodicity cells. The broken lines
in Figures 2b and 2b, and in some next figures, describe the
stress distribution in the homogeneous pipe with the parameter
E* and *.
The radial stress in the considered problem can be treated as
a macro-characteristic, which does not depend on the choice
of component of the periodicity cell. The calculations show
that the proposed homogenization method allows to calculate,
with a good accuracy, not only the macro-characteristics, but
also micro-characteristics, which values depend on the choice
of the considered component of periodicity cell. An example
of such micro-characteristic is the behaviour of the
circumferential stress, which is shown in Figure 3. When the
homogenization method is applied, there is no information
connected with the kind of ring layer in the specified point of
pipe. At each point we obtain two equations to calculate the
circumferential stress. The equation with the index 1 allows to
determine of the circumferential stress in the ring layer of the
first kind, and the one with the index 2 - in the ring layer of the
second kind. Two continuous lines denoted by numbers 1 and
2 (the indexes of types of layers) are appropriate for the values
Table 1. Dependence of the tensile stress values on the dimensionless parameter E1/E2 and the number of periodicity cells m
max ( r0 )
Hom.
m = 40
m = 20
m = 10
E1/E2 = 5
3.2954
-1.182%
-2.341%
-4.590%
E1/E2 = 10
4.0037
-1.770%
-3.495%
-6.804%
E2/E1 = 5
1.1103
0.905%
1.800%
3.562%
E2/E1 = 10
1.4982
0.897%
1.763%
3.405%
( p)
p0
( )
max
( r0 )
p
p0
( )
max
(1)
th
E11 0
( )
max
(1)
th
E11 0
a)
1
b)
0.6
(zzp ) p0
0.8
2nd kind layer
r
0
1th kind layer
0.6
(zzth )
E110
0.5
0.6
0.7
Homogeneous pipe
0.8
0.9
1
0.4
Homogeneous pipe
-0.6
1th kind layer
0.2
0
0.5
-0.2
-0.4
0.6
0.7
0.8
0.9
r
1 -1.2
2nd kind layer
m=10
-1.8
m=10
Figure 4. Distribution of axial stress along the pipe thickness; Figure 4a: for the axial stress caused by normal pressures; 4b: for
the ones caused by temperature differences; m = 20; 4a for E1/E2 = e; 4b for E2/E1 = e; the grey lines and rhombuses for e = 5; the
black lines and rhombuses for e = 10
1437
In the Table 1 the highest values of tensile stress calculated
using the homogenization method (column “Hom.”) are given.
The relative deviations (given in percent’s) obtained when
comparing the values with adequate values received in the
direct approach for the numbers of periodicity cells: columns
m=40, 20, 10. Based on the results presented in Table 1, it can
be concluded that the double increase in layer number caused
the double decrease in the difference between the stress
analysed. It means, that for the adequate number of cells, the
mathematical model of the problem can be based on the
homogenization method.
The results analogous to analysed ones are obtained in the
case of the axial stress, see Figure 4.
Substituting the constitutive relations (6a) and (10) into the
equilibrium equation of a representative cell.
hom
hom
d rrhom rr −
+
=0
dr
r
(32)
the following differential equation to determine of radial
averaged displacement within the representative cell is
obtained:
A1
6. THE MODELLING OF GRADIENT PIPE
d 2 uhom 1 d
du
dB u
+
=
( rA1 ) hom − A2 − r hom
r dr
dr
dr r 2
dr 2
d ( 1Thom ) ( 1 − 2 )
=
+
Thom , r ( r0 ,1) .
dr
r
(33)
The boundary conditions still have the form of Eqns. (5).
The solution of differential Eq. (31), which satisfies the
boundary conditions (5b) is given in the form:
Let the parameter describe the structure of considered
nonhomogeneous pipe changes along the pipe thickness (see
Figure 5). In the case where every pipe component is
considered as an independent thermoelastic body (direct
approach), the procedure for solving the problem is the same
as in the case of a pipe with periodic structure. As before, Eqns.
(1) will be solved and next the boundary conditions (2) and (3)
will be used, so the problem will be reduced to solving the
linear system algebraic Eqns. (20) and (21).
Thom ( r )
0
−1
1
1
dx
dx
=
,
r xK hom ( x ) r xK hom ( x )
0
r0 r 1.
(34)
It will be additionally assumed that the function (r) is the
linear function which satisfies the conditions (r0) = 1, (r0) =
0:
(r ) =
1− r
, r0 r 1
1 − r0
(35)
This kind of gradient material is used as a gradient coating
to protect of the slowly changing transition from the material
properties of substrate to the material properties of the material
of external (or internal) insulating coating. For some
simplification of the analysis, in this article, the gradientpassing ring layer will be considered independently. The
investigations will be limited to the thermal stress, so in the
boundary condition (5a) it will be assumed that p0 = 0.
Taking into account the relation (35), the function Thom(r),
after integration in the Eq. (34), can be written in the form:
Figure 5. The scheme of considered problem
Consider the possibility of applying of the relations (6) and
(10) to the description of the gradient body. Eqns. (6) and (10)
should be supplemented by the relation determining the heat
flux in the direction to layering:
Thom ( r )
0
=
1 − r + K A ln ( r )
1 − r0 + K A ln ( r0 )
, r0 r 1
(36a)
where,
qr = − K hom
dThom
dr
(30a)
KA =
K1r0 − K 2
K1 − K 2
(36b)
where,
K hom
K1 K 2
=
K 2 + (1 − ) K1
The differential Eq. (33), which is an equation with
changing coefficients, will be solved numerically using the
finite difference method. The interval [r0,1] is divided into N
equal subintervals. In every internal node the differentials in
Eq. (33) are replaced with well-known difference equations
based on the nodes. In this manner, we will obtain the
equations in the number N-1, which includes (n+1) unknown
parameters described the values of the radial displacement ui
= uhom(i) in the nodes i = r0 + ir, where r = (1- r0)/N, i =
0, 1, ..., N:
(30b)
Taking into account the dependence of parameter on the
variable r, the equation of heat conduction has the form:
dT
d
rK hom ( r ) hom
dr
dr
=0
(31)
1438
ui −1 − 2ui + ui +1 + 0.5ai r ( ui +1 − ui −1 ) − bi ( r ) ui =
by two equations obtained by substituting the constitutive
relations (6a) into homogenous equivalents of the boundary
conditions (5a). In the obtained relations, the differential
duhom/dr on the internal ends are replaced by the well-known
difference equations based on five nodes
2
= ci ( r ) , i = 1, 2,..., N − 1,
2
(37)
where,
1 d ( rA1 )
, r = i , i = 1, 2,..., N − 1
rA1 dr
ai =
bi =
1
dB
A2 − r
, r = i , i = 1, 2,..., N − 1
dr
r 2 A1
ci =
r
(38a)
dr
=−
25
4
1
u0 + 4u1 − 3u2 + u3 − u4
12
3
4
(39)
The equation for the differential at the right end r = 1 is
obtained from Eq. (39), substituting the parameter r by the
parameter -r, and index i (i = 0, 1, 2, 3 and 4) replacing by
the index N-i.
The calculations are performed for the parameters N and 2N,
selecting the parameter N in such a manner that the difference
between obtained approximations of radial displacement does
not exceed 0.5%. The calculations show that the required
accuracy will be received, if N=40 or N=80 in the dependence
on parameters.
b)
(38b)
1 d ( 1Thom ) ( 1 − 2 )
+
Thom ,
A1
dr
r
duhom ( r0 )
(38c)
r = i , i = 1, 2,..., N − 1.
The obtained system of equations should be supplemented
a)
0
0.3
u
0.5
0.6
0.7
r
0.8
0.9
1
-0.05
e=5
e=10
-0.1
0.15
-0.15
e=5
-0.2
e=10
-0.25
0
0.5
0.6
0.7
0.8
0.9
r
1
-0.3
-0.35
-0.15
m=20
-0.4
(rrth )
E **0
m=20
Figure 6. Distribution of dimensionless radial displacement, Figure 6a; and dimensionless radial stress, Figure 6b along the pipe
thickness: m = 20; black laines and rhombuses for E1/E2 = e > 1; grey laines and rhombuses for E2/E1 = e > 1
Thermal stress is related to the parameter E**0. The stress
state in the homogenized model depends on the six
dimensionless parameters: r0, E1/E2, 1, 2, 1/2 and K1/K2. If
the pipe non-homogeneity is taken directly into consideration,
number of representative cells m is also an additional
parameter. The assumptions presented in Section 5 “Result
analysis” beyond assumption 20, which will be replaced by the
relation (35) determined the form of function (r), are given
into consideration.
The distributions of macro-characteristics that is
characteristics averaged within the representative cell, are
presented. Figure 6a shows the radial displacement along the
thickness of the pipe, and Figure 6b presents the radial stress.
The distributions of radial displacement and stress in the
substitutive gradient pipe, which properties are determined
using the homogenization, are given by the continuous lines.
The distributions that considered directly the nonhomogeneity are presented as rhombuses. One can observe
complete qualitative agreement and a very good quantitative
agreement of both solutions.
It should be noted that if E1/E2 > 1 (the black lines in Figure
6), the material with thermal properties of the insulator (K1/K2
< 1, as follows from the assumption 4 presented in Section 5
for the choice of the parameters investigated) is on the internal
pipe surface. If E1/E2 < 1 (K1/K2 > 1, the grey lines in Figure
6) the insulating properties are on the outer surface of the pipe.
That is, that the gradient materials described by the parameters
E1/E2 and E2/E1 (E1/E2=E2/E1=e), have fundamentally
different thermomechanical properties. For this reason, the
black and grey lines (or rhombuses) in Figures 6 differ
considerably.
Figures 7 show the distribution of circumferential stress,
which in the considered problem depend on the kind of
component in the representative cell, so the stress is a microcharacteristics. The lines with number 1 are for the ring layers
with a greater Young modulus, and the lines with number 2 for
the layers with a smaller Young modulus. As is seen from
these figures, the solution of the problem based on the
homogenized model also in this case allows one to correctly
1439
representative cells m. For the minimization of the influences
of numerical errors during the calculations, the values in the
column “Hom.”, it was assumed that N=320. Based on the
results of calculations from Table 2 it can be concluded that
double increase of the cell number causes almost double
decrease in the difference between the stress analysed. That is,
that also in the case of gradient solids for adequate numbers of
cells, the mathematical model can be based on the
homogenization method. It can be emphasized that the
difference between the solution is greater if E1 > E2 (K1 < K2),
so the properties of the insulator are on the internal surface of
the pipe.
determine the stress state in every component of the
representative cell.
For the determination of quantitative differences between
the solutions based on both considered approaches, the Table
2 is presented. In the column “Hom.” in Table 2 the values of
circumferential stress on the internal and external pipe
surfaces obtained on the basis of homogenization method are
presented. It was assumed that in the point r = r0 there is the
first ring layer of the representative cell, and in the point r = 1
there is the second layer. In the subsequent columns, the
relative deviations (in percent) of these values from the
adequate values are obtained considering the number of
a)
1.5
1
b)
2
(th )
E **0
1
th )
(
1
E **0
1
0
0.5
0.5
0.6
0.7
-1
0
0.5
0.6
0.7
0.8
0.9
r
2
-0.5
0.9
r
1
2
1
-2
-1
-3
-1.5
-4
m=20
-2
0.8
m=20
-5
Figure 7. Distribution of circumferential stress along the pipe thickness: m = 20; the black lines and rhombuses are for E1/E2 =
e > 1; the grey lines and rhombuses are for E2/E1 = e > 1; Figure 7a for e = 5; 7b for e = 10; number 1 is adequate for
circumferential stress in layers with a higher Young modulus; number 2 is for circumferential stress in layers with a smaller
Young modulus
Table 2. Dependence of circumferential stress on the pipe surface on the dimensionless parameter E1/E2 and number of
representative cells m
( th )
( r0 )
* *
E 0
E1 > E2
( th )
(1)
* *
E 0
E1 > E2
E1 < E2
E1 < E2
E1/E2 = 5
E1/E2 = 10
E2/E1 = 5
E2/E1 = 10
E1/E2 = 5
E1/E2 = 10
E2/E1 = 5
E2/E1 = 10
“Hom.”
-0.8185
-1.0217
-1.4977
-1.7270
0.1568
0.09616
1.3866
1.8161
m = 80
-0.393%
-1.125%
0.118%
0.232%
-0.638%
-0.915%
0.343%
0.254%
m = 40
-0.761%
-2.192%
0.231%
0.444%
-1.262%
-1.820%
0.682%
0.508%
m = 20
-1.417%
-4.140%
0.443%
0.884%
-2.480%
-3.588%
1.348%
1.041%
m = 10
-2.467%
-7.410%
0.819%
1.674%
-4.788%
-6.957%
2.636%
1.979%
has periodic structure, the solution based on the
homogenization method takes the form of simple engineering
relations. Whereas if the pipe structure is investigated directly
in the thermoelastic problem, two systems of linear equations
with the dimension 4m, where m is the number of periodicity
cell, need to be solved.
When describing the gradient pipe using the
homogenization method, one will not obtain an analytical
solution. The numerical method was proposed, which leads to
a system of 40 – 80 linear algebraic equations. It seems that
within the framework of the considered problem, the
7. FINAL REMARKS
In the paper, it is shown, that in the framework of the
considered problems as well as for the multi-layered pipe with
the periodic structure and the multi-layered pipe with gradient
structure, the homogenized model can be applied. The
proposed approach to homogenization allows us to correctly
calculate not only the averaged characteristics in the
representative cell (the macro-characteristics) but also the
characteristics dependent on the choice of the component in
the representative cell (the micro-characteristics). If the pipe
1440
homogenization method is effective, when the number of
representative cells considerably exceeds the number 20. It can
be emphasized, that the presented investigations allow to
conclude, that the proposed homogenization method can
correctly describe the solutions of more complicated problems,
in which an independent consideration of representative cell
components can be extremely labour-consuming or sometimes
simply impossible to accomplish.
[11]
[12]
ACKNOWLEDGMENT
[13]
The research has been conducted as part of a project at the
Faculty of Mechanical Engineering of the Bialystok
University
of
Technology.
Project
number
WZ/WMIIM/3/2020.
[14]
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NOMENCLATURE
E
K
m
n
p0
R0
R1
(r, φ,
z)
T
u
Young modulus, MPa
thermal conductivity, W.m-1. K-1
number of the representative cells
number of the ring layers
normal pressure applied to the inner pipe surface,
MPa
outer radius of pipe, m
inner radius of pipe, m
dimensionless cylinder coordinates related to the
inner radius of pipe
temperature deviation in the points of pipe from
the temperature of outer medium, K
dimensionless radial displacement related to the
inner radius of pipe
Greek symbols
θ0
λ, µ
µ
σ
σrr
σφφ
σzz
1442
coefficient of linear thermal expansion, K-1
dimensionless thickness of representative cells
temperature difference in its inner and outer
surface of pipe, K
Lame’ constants, MPa
Kircchoff coefficients (the second Lame constant),
MPa
Poisson coefficient
tensor stress, MPa
radial components of stress tensor, MPa
circumferential components of stress tensor, MPa
axial components of stress tensor, MPa