Cultures grammaticales et demande métalinguistique

1997 : dans C. Tisset (dir.) : Actes du Colloque international du Groupe de recherche Jan Comenius en linguistique et didactique des langues (2 et 3 octobre 1996, Nanterre), LINX, n°36 vol.1 (pp. 131-137).

1999

Acquisition et interaction en langue étrangère, 1996

2001 : dans Bouquet S. (dir.) : Théories linguistiques et enseignement du français aux non francophones, Le français dans le monde, Recherches et applications, juillet, p. 59-80/

Studii de Lingvistica, 2019

The discourse of academic writing includes "metadiscursive" elements that allow the author to construct the structure of the text, to evaluate the content of the text or to express his own emotions. These metadiscursive elements are nonetheless central to an understanding of the rhetorical and argumentative functions of scientific discourse. Mastering these elements is particularly important for young researchers who aim to integrate with the scientific "discourse community" (Swales 1990). Among these metadiscursive elements, we find, in human sciences research articles, a remarkable number of reader guidance markers which aim to facilitate the comprehension of the reader through a set of functions. In this paper, we address metalinguistic markers, in particular metalinguistic routines, in order to observe their productivity and their semantic functions, on the one hand, and to question the rhetorical and argumentative function they perform in scientific discours...

Corela, 2004

Français, langue ardente, Actes du XIVe congrès mondial de la Fédération internationale des professeurs de français , 2018

2004 Présentation du numéro 154 de la revue Langages que J.-C. Beacco a conçu et coordonné **** Contributions de Py, Traverso, Moore, Tabouret-Keller...**** Lien vers les articles.

Problems 1-1 through 1-6 are for student research. No standard solutions are provided. 1-7 From Fig. 1-2, cost of grinding to  0.0005 in is 270%. Cost of turning to  0.003 in is 60%. Relative cost of grinding vs. turning = 270/60 = 4.5 times Ans. ______________________________________________________________________________ 1-8 C A = C B , 10 + 0.8 P = 60 + 0.8 P  0.005 P 2 P 2 = 50/0.005  P = 100 parts Ans. ______________________________________________________________________________ 1-9 Max. load = 1.10 P Min. area = (0.95) 2 A Min. strength = 0.85 S To offset the absolute uncertainties, the design factor, from Eq. (1-1) should be