Received: 26 January 2018
|
Accepted: 26 July 2018
DOI: 10.1111/jmg.12446
ORIGINAL ARTICLE
Relation between mean stress, thermodynamic, and lithostatic
pressure
Evangelos Moulas1
| Stefan M. Schmalholz1 | Yury Podladchikov1 |
Lucie Tajčmanová2 | Dimitrios Kostopoulos3 | Lukas Baumgartner1
1
Institute of Earth Science (ISTE),
University of Lausanne, Lausanne,
Switzerland
2
Department of Earth Science, ETH
Zurich, Zurich, Switzerland
3
Faculty of Geology & Geoenvironment,
National & Kapodistrian University of
Athens, Athens, Greece
Correspondence
Evangelos Moulas, Institute of Earth
Science (ISTE), University of Lausanne,
Lausanne, Switzerland.
Email: evangelos.moulas@unil.ch
Funding information
University of Lausanne; ERC, Grant/
Award Number: 335577
Abstract
Pressure is one of the most important parameters to be quantified in geological
problems. However, in metamorphic systems the pressure is usually calculated
with two different approaches. One pressure calculation is based on petrological
phase equilibria and this pressure is often termed thermodynamic pressure. The
other calculation is based on continuum mechanics, which provides a mean stress
that is commonly used to estimate the thermodynamic pressure. Both thermodynamic pressure calculations can be justified by the accuracy and applicability of
the results. Here, we consider systems with low‐differential stress (<1 kbar) and
no irreversible volumetric deformation, and refer to them as conventional systems.
We investigate the relationship between mean stress and thermodynamic pressure.
We discuss the meaning of thermodynamic pressure and its calculation for irreversible processes such as viscous deformation and heat conduction, which exhibit
entropy production. Moreover, it is demonstrated that the mean stress for incom-
Handling Editor: Doug Robinson
pressible viscous deformation is essentially equal to the mean stress for the corresponding viscous deformation with elastic compressibility, if the characteristic
time of deformation is five times longer than the Maxwell viscoelastic relaxation
time that is equal to the ratio of shear viscosity to bulk modulus. For typical lithospheric rocks, this Maxwell time is smaller than c. 10,000 years. Therefore,
numerical simulations of long‐term (>10 kyr) geodynamic processes, employing
incompressible deformation, provide mean stress values that are close to the
mean‐stress value associated with elastic compressibility. Finally, we show that
for conventional systems the mean stress is essentially equal to the thermodynamic pressure. However, mean stress and, hence, thermodynamic pressure can be
significantly different from the lithostatic pressure.
KEYWORDS
geodynamic models, lithostatic pressure, local thermodynamic equilibrium, mean stress, thermodynamic
pressure
1
| INTRODUCTION
Metamorphic rocks are a unique window to conditions prevailing in the earth's crust and mantle. Thermodynamic
pressure and temperature (P–T) information is culled from
J Metamorph Geol. 2018;1–14.
mineral modal amounts, mineral chemistry, and/or
microstructures, thought to reflect a state of equilibrium
attained at some point during rock history (e.g., Spear,
1993). Key parameters such as thermodynamic pressure (P)
and temperature (T) are often the outcome of complex
wileyonlinelibrary.com/journal/jmg
© 2018 John Wiley & Sons Ltd
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calculations involving minimization of the Gibbs free
energy of a system (e.g., Connolly, 2005; De Capitani &
Brown, 1987; De Capitani & Petrakakis, 2010; Karpov,
Chudnenko, Kulik, & Bychinskii, 2002; Kulik, 2002;
White, Johnson, & Dantzig, 1958). In most of these calculations, it is implicitly assumed that the thermodynamic
pressure of the reacting mixture is the same for all fluid/
mineral phases present. This is likely a good approximation
in cases wherein the metamorphic assemblage is under low
differential stress (<~1 kbar), the irreversible volumetric
deformation is negligible and is, therefore, commonly
employed in phase equilibria experiments.
On the other hand, geodynamic models help us understand the thermomechanical evolution of rocks by using
mass, energy, and momentum conservation equations as
well as constitutive relations that describe material behaviour (e.g., Gerya, 2010; Turcotte & Schubert, 2014).
Such models usually result in the calculation of stress
and temperature evolution in deforming regions. A major
challenge here is to establish a link between the stress
state of a deforming rock and its thermodynamic pressure, i.e., the pressure that can be used in metamorphic
phase equilibria. A common practice in geodynamic
modelling is to use mean stress as a proxy for the thermodynamic pressure of the system considered. However,
there are cases where this approximation may not be
valid (e.g., Dahlen, 1992).
Hobbs and Ord (2017) have recently suggested that
thermodynamic pressure can be defined only for processes where entropy does not change with time (i.e.,
isentropic). Similarly, Powell, Evans, Green, and White
(2017) have also stated that equilibrium thermodynamic
calculations cannot be applied to situations where irreversible deformation, as an entropy‐producing process,
takes place. If true, this would have significant consequences for earth sciences where natural processes are
most probably never isentropic and entropy production is
never zero due to irreversible processes, such as radiogenic heat production, chemical diffusion, viscous deformation, and the ever‐present heat conduction. Moreover,
according to Hobbs and Ord (2017), the use of viscous
incompressible formulation, a commonly used approximation in geodynamics to quantify the magnitude of mean
stress in deforming rocks, is inappropriate to estimate
thermodynamic pressure since volume deformation is not
being taken into account. The aforementioned statements
challenge the link between the common geodynamic
models of rock deformation that involve dissipative
processes, and calculations of metamorphic recrystallization.
The purpose of this study is to demonstrate that thermodynamic pressure can be safely defined for nonisentropic processes, and that equilibrium thermodynamic
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calculations are certainly applicable when considering conventional systems for which differential stress is low and
irreversible volumetric deformation is negligible. In addition, we show that the incompressible approximation of
viscous flow yields accurate mean‐stress estimates for
deforming viscous rocks that are elastically compressible.
Finally, we establish that the thermodynamic pressure of
conventional systems may be significantly different from
the lithostatic pressure. An assessment of unconventional
models that consider large differential stress or dramatic
effects of low‐differential stress on mineral phase equilibria
(e.g., Schmalholz & Podladchikov, 2014; Tajčmanová,
Vrijmoed, & Moulas, 2015; Wheeler, 2014) is beyond the
scope of this work.
2 | HYDROSTATIC STRESS AND
LITHOSTATIC PRESSURE
By definition, isotropic‐stress conditions are those where
all normal stress components are equal to a mean‐stress
value, and shear stresses are zero. This state of stress is
known as hydrostatic. A fundamental result of hydrostatics,
i.e., the study of fluids at rest, is that under the influence
of gravity only, the stress state is isotropic and the mean
stress at any point in a fluid is related to the weight of the
overlying fluid column. The relation between hydrostatic
pressure, which in this case is equal to mean stress, and
depth is given by the formula (e.g., Batchelor, 1967, p.
19):
dPh
¼ ρg
dz
(1)
where Ph is the hydrostatic pressure (Pa), z the depth (m),
ρ the density (kg/m3), and g the acceleration of gravity
(m/s2). If one assumes constant density and constant gravity acceleration, the above relationship can be integrated to
provide the expression for Ph (e.g., Batchelor, 1967, p. 20):
Ph ðzÞ ¼ P0 þ ρgðz
z0 Þ
(2)
where P0 is the reference hydrostatic pressure at depth z0.
This expression has been extensively used in the geological
literature for the calculation of depth of metamorphic
recrystallization. Interestingly, it inherently contains the
assumption that density remains constant during integration
with respect to depth (z) and, therefore, the result is valid
only for incompressible fluids at rest. When rocks are considered, Ph is commonly referred to as lithostatic pressure
(PL), i.e., pressure that results only from the weight of static rocks (Bucher & Frey, 2002, pp. 72–73). In fact, there
is no particular justification why stresses in the earth
should be considered lithostatic except for simplicity reasons (e.g., Jaeger, 1969, p. 172).
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3 | THERMODYNAMIC
RELATIONSHIPS
du ¼ Tds
By definition, state functions are independent of the path
followed by the physical processes (i.e., isothermal or isentropic etc.). The experimental basis of thermodynamics is
the recognition of the volume (m3), temperature (K), and
thermodynamic pressure (Pa) as fundamental state variables. Thermodynamic pressure is defined as the force
f (N) acting perpendicularly on a unit of area A (m2) (e.g.,
Kondepudi & Prigogine, 1998, p. 9):
P¼
f
A
(3)
This definition applies to gases, fluids, and solids under
isotropic‐stress conditions and without irreversible
volumetric deformation. Another experimental finding in
thermodynamics is the establishment of path‐ and process‐
independent relationships between state functions, commonly known as equations of state (EOS). When expressed
for density, EOS are functional relationships of the form:
ρ ¼ ρðT; PÞ
(4)
A typical example for an EOS is the ideal‐gas law:
ρðT; PÞ ¼
MP
RT
(5)
where R is the universal gas constant and M is the molar
mass of the gas. For more complex fluids, many other
formulations can be used (e.g., Ferry & Baumgartner,
1987). By definition, EOS are independent of the path
followed by the physical processes (i.e., isothermal or
isentropic etc.). More complex EOS can be found in the
literature regarding the density of minerals as a function
of P and T (e.g., Anderson, 1995). Note that EOS apply
regardless if the operating processes are infinitely slow
or not.
Having the EOS of a substance is sufficient to describe
its density as a function of P and T but not its energy. In
quasistatic fluids, for example, the work increment (dW)
done by P is (e.g., Fermi, 1936):
dW ¼ f dx ¼ PAdx ¼ PdV
(6)
where dx is the displacement in the direction of the force f
and A is the area normal to f. The latter equation implies
that P is the proportionality factor between mechanical
work and volume change. For a finite volume change, the
mechanical work can be obtained by integrating Equation 6. If chemical composition and temperature are taken
into account, then, the variation of the specific internal
energy (du) is given by (e.g., De Groot & Mazur, 1984,
p. 458):
Pdν þ ∑ck¼1 μk dwk
3
(7)
where u (J/kg) is the specific internal energy of the fluid, T
(K) is the temperature, s (J K−1 kg−1) is the specific
entropy, P (Pa) is the thermodynamic pressure, ν (m3/kg)
is the specific volume, μk (J/kg) is the chemical potential of
the kth component, wk is the total mass of the kth component divided over the total mass of the system, c is the
number of components and d represents the exact differential. Note that the energy (u), entropy (s), volume (ν), and
chemical potential (μ) are given per unit mass (kg). Naturally, thermodynamic pressure can then be back‐calculated
from internal energy by partial differentiation of Equation 7
(e.g., Callen, 1960, p. 31; Landau & Lifshitz, 1976, p. 42):
@u
P¼
(8)
@ν s;wk
According to Equation 8, the thermodynamic pressure
(P) is the proportionality factor (with a minus sign) of the
internal‐energy increment to volume change when entropy
(s) and composition (components wk) are kept constant
during partial differentiation.
The reason why we go at such length in clarifying the
issue is the recent statement by Hobbs and Ord (2017) that:
“the thermodynamic pressure, the chemical potentials, and
the stress are only defined, inter alia, at constant entropy,
so that although the entropy may change during the evolution of a metamorphic system as deformation and chemical
reactions proceed we are only interested in states where the
entropy production is zero, expressed as s ¼ 0 where the
over‐dot denotes differentiation with respect to time”. This
reasoning led the previous authors to the conclusion that
“the role of tectonic pressure is only relevant to phase equilibrium when an equilibrium thermodynamic pressure can
be defined” and thus for isentropic (i.e., s ¼ 0) processes
only.
Following the logic of Hobbs and Ord (2017), it is not
entirely clear why entropy has to remain constant during
an actual physical process in order for pressure (P) to be
“usefully defined”. One way to interpret the statement of
Hobbs and Ord (2017) is to relate it with the “definition”
of P by Equation 8. This would imply that the previous
authors interpreted the constraint of s being constant (during partial differentiation) in Equation 8 as a requirement
of s to be constant in an actual physical process. If this is
the case, then the aforementioned statement is incorrect on
mathematical grounds for two reasons. First, entropy differ
entiation with respect to time (expressed as s ¼ 0) does not
necessarily mean that entropy production is zero (see
Appendix 1 for details). Second, keeping s constant during
partial differentiation (Equation 8) does not mean that P is
defined only for processes where s is constant in time.
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From a mathematical perspective, partial differentiation of
any function [e.g., u(s, ν, wk)] keeping certain variables
constant (e.g., s), leads to a new function that contains the
same variables as the original one. Therefore, Equation 8
that was derived from partial differentiation of Equation 7,
keeping s constant, is a function of the same variables as
those that define Equation 7, i.e., s, ν, wk, even though s
was kept constant during partial differentiation. Keeping
certain thermodynamic variables constant during partial differentiation does not place any constraints on the use of
the derived functions with respect to the variables that were
kept constant. By definition, state functions are functions
of the state and are not sensitive to the process(es) that led
to that particular state. A more familiar example in this
case would be the usage of EOS for minerals where volume (V) is commonly given as a function of P–T. For illustration purposes, we will consider the EOS as it is used by
Holland and Powell (1998), in order to calculate the bulk
modulus KT:
1
1
@VðP; TÞ
¼
KT ðP; TÞ
V ðP; T Þ
@P
T
(9)
1
¼
K298 ð1 1:5 10 4 ðT 298ÞÞ þ 4ðP 1Þ
sound (c.f. Müller & Weiss, 2005, p. 3) and this is evident
by the numerous industrial applications of thermodynamics,
combustion engines and shock‐wave EOS for solids (c.f.
Müller & Müller, 2009). In that respect, geodynamic processes take place at sufficiently slow rates for the application of equilibrium thermodynamics relationships and
hence P is well‐defined for nonisentropic geodynamic
processes.
Last but not least, if Equation 8 was the only way to
“usefully” define thermodynamic pressure in petrology,
then the a priori knowledge of the specific‐energy function
(u) is required in order to perform partial differentiation. In
other words, one has to know u in order to be able to
determine P. However, in petrology the free energy and
other thermodynamic potentials are calculated by using
EOS that assume knowledge of pressure (P). It is therefore
the energy, which is usually calculated from the pressure
and not vice versa.
where K298 is the isothermal bulk modulus (bar) measured
at 298 K and 1 bar. The value of K298 is tabulated by Holland and Powell (1998) for a large number of minerals. We
emphasize here that although KT was calculated by partial
differentiation by keeping temperature constant, it is a
function of both P and T and can be used for any P–T path
chosen including nonisothermal processes. Similar conclusions can be drawn if one uses different energy functions
to calculate pressure (see Appendix 2 for details).
Based on the arguments presented in the previous paragraph, it is not possible to justify the Hobbs and Ord
(2017) statement regarding the definition of pressure on
mathematical grounds. Alternatively, we can consider the
statement that entropy has to remain “constant” for the definition of pressure stems from interpretations of equilibrium
thermodynamics. It is common in classical equilibrium
thermodynamics to consider sufficiently slow and quasistatic processes where it is assumed that time derivatives
related to the physical processes vanish. But, does quasistatic mean that the physical processes are infinitely
slow? If the thermodynamic pressure (among other variables) could be defined only for isentropic processes, as
Hobbs and Ord (2017) suggest, then even the simplest
examples from equilibrium thermodynamics would be
invalidated. An example would be a thermodynamic cycle
(e.g., Carnot, Otto) where s is generally changing during a
cycle and yet P can be defined at every part of the cycle.
However, sufficiently slow could be as fast as the speed of
It is commonly held that equilibrium thermodynamic relationships (e.g., Equations 7 and 8) are justified only when
a system is very close to thermodynamic equilibrium, or
when all ongoing processes are reversible. In other words,
equilibrium thermodynamics applies when metamorphic
reactions have small overstepping with respect to the equilibrium‐reaction boundaries, chemical diffusion has homogenized minerals on a certain scale, thermal diffusion has
equilibrated the temperature on the same scale and last, but
not least, viscous relaxation has relaxed all differential
stresses. In fact, this is a sufficient but not a necessary condition for the application of equilibrium thermodynamic
relationships.
In order to apply equilibrium thermodynamics in petrology, the concept of local equilibrium is used in one way or
another, since metamorphic systems are never in global
equilibrium and there are ever‐present dissipative processes
like conductive cooling of the Earth. The framework of
classical irreversible thermodynamics (CIT) is the established way to quantify far‐from‐equilibrium processes, such
as thermal convection (e.g., De Groot & Mazur, 1984;
Lebon, Jou, & Casas‐Vázquez, 2008; Müller & Müller,
2009). The foundation of CIT is the assumption of local
thermodynamic equilibrium, according to which: “local and
instantaneous relations between thermodynamic quantities
in a system out of equilibrium are the same as for a uniform system in equilibrium” (Lebon et al., 2008, p. 39). In
other words, CIT assumes that Equations 7 and 8 are
4 | THE ASSUMPTION OF LOCAL
THERMODYNAMIC EQUILIBRIUM:
WHAT DOES IT REALLY MEAN?
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satisfied even in reacting and deforming systems far from
equilibrium.
The studies of CIT require constitutive relationships
such as EOS (e.g., Equation 4). The applicability of such
relationships applies also for dynamic systems as witnessed
by the shock‐wave EOS for minerals (e.g., Ahrens, 1987,
1993), combustion thermodynamics (e.g., Powers, 2016)
detonation waves (e.g., Müller & Müller, 2009; Powers,
2016), kinetics (e.g., Lasaga, 1998), and other dynamic
processes. The simplest example of an irreversible geological process is the temperature evolution during simple heat
conduction, where the caloric equation of state, an equilibrium thermodynamics relationship, must be used in order
to relate changes in energy with changes in temperature.
Similarly, simple chemical diffusion utilizes the equilibrium
chemical potential (i.e., activity–composition) relationships
when diffusion in minerals is quantified. Even if a body is
capable of performing pure elastic deformation, thermal
elasticity generally requires the development of temperature
gradients under elastic strains. Consequently, temperature
gradients will induce thermal diffusion and dissipation
(e.g., Zener, 1937, 1938). Similar conclusions can be
drawn for the case of chemical diffusion in minerals.
Contrary to CIT, the applicability of equilibrium thermodynamics in dissipative systems has been recently challenged (e.g., Hobbs & Ord, 2017; Powell et al., 2017). If
true, the ever‐present geothermal gradient, associated with
dissipative heat conduction and radiogenic heat production,
would preclude the usage of equilibrium thermodynamics
during the whole history of the Earth (for a more formal
definition of dissipative systems and the difference between
entropy‐producing and nonisentropic processes see
Appendix 1).
5 | THERMODYNAMIC AND
GEODYNAMIC CALCULATIONS
There are two types of calculations that are commonly
employed in geology, namely thermodynamic and geodynamic. These calculations are based on different sets of
assumptions, which can be justified by the accuracy and
applicability of the computed results. Elaborate EOS quantifying volumetric changes are often involved in order to
accurately predict phase boundaries at phase diagrams and
physical properties according to experiments (e.g., Anderson, 1995). By contrast, geodynamic calculations often
neglect the volumetric deformation of the materials (i.e.,
they follow the incompressible approximation) but still
yield physically accurate and meaningful results that reproduce fluid‐dynamic experiments (e.g., thermal convection;
Schubert, Turcotte, & Olson, 2001; Turcotte & Schubert,
2014) or other geologically relevant structures (e.g., Pollard
5
& Fletcher, 2005). Worth noting here is that the most‐commonly used expression for lithostatic pressure (Equation 2)
in petrological interpretations is derived by integrating
Equation 1 assuming constant density and this, strictly
speaking, also follows the incompressible approximation.
In the ensuing paragraphs, we present cases to demonstrate
the applicability and accuracy of the incompressible
approximation in geodynamic models.
5.1
| A static case
In order to demonstrate that the incompressibility assumption is valid for first‐order approximations of geodynamic
problems, we will modify Equation 1 to include the effects
of elastic compressibility of solids. For this demonstration,
the effects of increasing temperature with depth (namely
thermal expansion) are neglected because the thermal
expansion counteracts the effect of the P‐related increase in
density with depth. Hence, the maximum effect of compressibility (assuming that composition is constant) is
inherent in the following calculations. First, density is a
function of P and is given by the relation:
dρ
¼ βdP
ρ
(10)
where β is the material compressibility (Pa−1) and an isotropic material has been considered. Compressibility is the
inverse of bulk modulus and can also depend on P and
other factors like temperature (e.g., Equation 9) or composition, but we will consider it constant for now. Integration
of Equation 10, assuming a reference density (ρ0) measured
at reference P0, yields the following expression for density
as a function of P:
ρ ¼ ρ0 eβðP
P0 Þ
(11)
Inserting Equation 11 into Equation 1 and integrating (assuming g is constant) yields an expression that relates
depth (m) to P (Pa):
z¼
1
eβðP0
βρ0 g
PÞ
(12)
For comparison purposes, the corresponding expression
assuming constant density yields the standard expression
for the lithostatic pressure and its relation to depth:
z¼
P0 P
ρ0 g
(13)
Substitution
of average
values
for
feldspar
(ρ0 = 2,620 kg/m3, β = 1.82·10−11 Pa−1) in Equations 12
and 13 shows that the P correction for elastic compressibility is negligible compared to the incompressible approximation (Figure 1).
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(a)
(b)
F I G U R E 1 (a) Lithostatic pressure profiles (PL). The solid line
(PcL ) is the lithostatic pressure predicted by a compressible
formulation (Equation 12) and the black diamonds (PiL ) show the
lithostatic pressure predicted by the incompressible approximation
(Equations 2 and 13). The lithostatic pressure is given in GPa and the
difference between PcL and PiL is almost indistinguishable. The
acceleration of gravity (g) is taken as 9.81 m/s2 and the
compressibility is approximated by a representative value for
feldspars (55 GPa)−1 according to Angel (2004a, 2004b). (b) The
pressure difference (MPa) between the two lithostatic pressures, PcL
and PiL
5.2
| A dynamic case
In the case of deforming rocks, such analytical integration
as the one presented in Section 5.1 is not easily performed
and more complex mechanical models are needed. Over
recent years, a number of theoretical models based on continuum mechanics have been presented in an attempt to
quantify mechanical and thermodynamic variables in evolving metamorphic systems where deformation and recrystallization occur simultaneously (Gerya, 2015; Mancktelow,
2008; Moulas, Podladchikov, Aranovich, & Kostopoulos,
2013; Tajčmanová et al., 2015, and references therein). In
these studies, it has been suggested that field variables such
as stress need not be homogeneously distributed and certainly mean stress cannot always be a simple function of
depth. Several reasons can be responsible for large or small
deviations from lithostatic pressure and they involve topography changes, density variations, tectonic loading, volumetric deformation, viscosity heterogeneities etc.
Contrary to most engineering studies on solids, geological studies investigate processes where the shear strain during rock deformation can be orders of magnitude larger
than volumetric strain. This difference in strain is the main
reason why the incompressible approximation is widely
used in geodynamic calculations. In addition, due to the
large time‐scales involved in geological deformation, some
ET AL.
models consider only the viscous deformation of rocks by
treating them as highly‐viscous fluids. The mean stress predicted from such models is usually equated with pressure
derived from equilibrium phase assemblages (Burg & Gerya,
2005; Gerya, Perchuk, & Burg, 2008; Reuber, Kaus, Schmalholz, & White, 2016; Schmalholz, Duretz, Schenker, & Podladchikov, 2014; Sizova, Gerya, & Brown, 2012). Hobbs and
Ord (2017) suggested that: “except for elastic deformations,
mean stress is not useful in discussing mineral phase equilibrium”. Nevertheless, ignoring compressibility in models of
viscous deformation does not mean that thermodynamic pressure cannot be defined or its corresponding value is inaccurate. As shown in Figure 1, considering a lithostatic pressure
(PL) gradient assuming constant density (Equation 2), yields
a PL estimate that is directly comparable to that calculated by
additionally considering volumetric deformation (Equation 10). Similarly, the mean stress calculated from incompressible viscous deformation can be quite similar to the
mean stress calculated from elastic volumetric deformation.
To illustrate this point, let us ponder a simplified geological
scenario of viscous deformation (for details on the model see
Supporting Information Appendix S1). Here, a layer 10 times
more viscous than its surroundings is compressed in pure
shear under the influence of gravity (Figure 2). Both the
matrix and the layer are taken to be isotropic and elastically
compressible having no irreversible volumetric deformation.
The materials are thus elastic with respect to volumetric
deformation and purely viscous with respect to shear deformation. This approximation is commonly employed when
long geodynamic time‐scales are considered (>~1,000 year).
In this example, pressure is the mean stress that is used in the
elastic EOS and therefore, for this example, mean stress (σm)
and thermodynamic pressure (P) are synonymous. We will
examine three cases of varying bulk modulus along with an
incompressible case for reference.
In the absence of tectonic loading, the calculated mean
stress is equal to the lithostatic pressure (Figure 3a). Note
that, in this simplified example, there is no topography and
there are no horizontal gradients of density that would
require differential stresses to be supported. Once a tectonic
compressive stress is imposed at the sides, the strong viscous layer exhibits a mean stress different from the lithostatic (Figure 3b). In this example, we consider temperature
and composition to be constant, hence mean stress and P
can be calculated using Equation 10. Since it is commonplace in mechanics to incorporate the bulk modulus (i.e.,
the inverse of compressibility) in the calculation of P,
Equation 10 can be modified as:
dP ¼
Kb
dV
V
(14)
where Kb is the isothermal bulk modulus (Pa) and the
materials are assumed to be isotropic. The second term in
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F I G U R E 2 Two‐dimensional model configuration. Pure shear of
a viscous layer embedded in a viscous matrix. The bulk rate of
shortening, ɛ_ b , is 10−14 s−1. Both the layer and the matrix are
elastically compressible and they have the same bulk moduli. Free
slip is imposed at all boundaries. The shear viscosity of the layer is
10 times larger than the one of the matrix. Gravity acts downwards in
a direction parallel to y. The reference density (ρ0) of the two
materials is considered to be the same and equal to 2,700 kg/m3.
Each side of the box is 1 km long. The description of the numerical
solution can be found in the Supporting Information Appendix S1
the right‐hand side of Equation 14 is the volumetric strain
due to elastic deformation. Equation 14 dictates that materials with larger bulk moduli will develop larger P for a
given elastic volumetric strain. The P evolution in the modelled layer has been investigated for three different bulk
moduli, namely 30, 60, and 100 GPa (Figure 4). Initially,
the model domain is subjected only to the gravitational
force (as in Figure 3a); P is close to the lithostatic
7
approximation from Equation 2, but not exactly equal to it
because density changes as a function of P. Once the
domain is compressed at the sides (as in Figure 3b), the
mean stress (σm; also equal to P in this case) in the highly
viscous layer deviates from the lithostatic pressure (PL) and
increases with time (Figure 4). Mean stress builds continually up to the value predicted for the incompressible case
for all three compressible materials and henceforth remains
constant provided that the layer keeps being compressed
(Figure 4). At a given time of 20 kyr, we remove the
exerted tectonic load and mean stress retreats back to its
lithostatic value.
The mean‐stress deviation that develops in the viscous
layer is proportional to the layer's far‐field stress, which
depends on the viscosity difference between the layer and
the matrix and its strain rate (e.g., Schmalholz & Podladchikov, 1999; Smith, 1975). The time needed for the
mean‐stress buildup/relaxation depends on the different
characteristic Maxwell times of the system (Figure 5). For
the studied case, the characteristic time is given by:
tM ¼
μl
Kb
(15)
where μl is the shear viscosity of the layer. This formulation looks similar to the Maxwell characteristic time for
shear deformation but we note that our model is purely viscous with respect to shear deformation and purely elastic
with respect to volumetric deformation. The applicability of
the lithostatic pressure formula (Equation 2) is actually also
restricted to time‐scales larger than this Maxwell relaxation
time, because the lithostatic formula assumes that differential stresses have been relaxed.
5.3 | Applications to systems with large
mean‐stress variations
The direct relation between thermodynamic pressure (P)
and mean stress (σm) may not apply to systems under high
F I G U R E 3 Mean stress (σm) calculated for the case of viscous incompressible deformation. (a) In the absence of imposed tectonic stress, σm
is given by the lithostatic formula. (b) In the case of pure shear of a viscous layer, the mean stress (σm) in the layer is different to the lithostatic.
In this example, the mean stress is equal to the thermodynamic pressure (P) that is used in the EOS if the material is considered to be
compressible. The vectors show the local velocity directions
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F I G U R E 4 Mean‐stress evolution (σm) in the centre of the
viscous layer (μl = 1021 Pa·s) for the case of compressible and
incompressible materials for the model configuration displayed in
Figure 2. Three different curves correspond to three different bulk
moduli and the solid black line indicates mean‐stress evolution
predicted in the viscous layer by the incompressible approximation.
The dashed horizontal line indicates the lithostatic pressure in the
absence of tectonic loading. Tectonic compression by pure shear
stops at a given time (here 20 kyr) and mean stress relaxes back to
the lithostatic pressure
differential stress (e.g., Sekerka & Cahn, 2004) and currently there are different views on the importance of the
differential stress on metamorphic phase equilibria (c.f.
Dahlen, 1992; Fletcher, 2015; Hobbs & Ord, 2015;
Wheeler, 2014). This situation becomes more complex for
fluid–rock interactions in porous rocks where interface conditions must be considered (c.f. Dahlen, 1992). Nevertheless, there are particular cases where rocks can experience
locally large mean‐stress variations from the lithostatic
(a)
ET AL.
pressure while themselves being under low differential
stress. Geologically relevant examples are shear zones and
inclusions that support low differential stress. As shown
already by Schmalholz and Podladchikov (2013), a shear
zone that develops during continental shortening will have
in general low differential stress but its mean stress may be
different from the lithostatic (Figure 6a,b). Although this
may be counterintuitive, it has been demonstrated that
weak zones (i.e., zones that cannot support high differential
stress) may develop significant mean‐stress deviations from
the far‐field mean stress, which in turn, will be different
from the lithostatic (Moulas, Burg, & Podladchikov, 2014;
Schmid & Podladchikov, 2003). This is also the case when
compressible materials are considered (Figure 7). The reason why this is possible is the ability of the surrounding
strong rocks to support high differential stresses (Figures 6c,d and 7). Factors that control the magnitude of the
mean‐stress variation in viscously deforming rocks are: (a)
the shape and orientation of the weak zones, (b) the viscosity ratio between the weak rocks and their surroundings,
and (c) the magnitude of the far‐field stress. Therefore, a
weak viscous inclusion or a weak shear zone within a
strong rock unit will experience a mean stress, which may
be considerably different from the lithostatic pressure and,
in extreme cases, can reach up to two to three times the
lithostatic pressure value (c.f. Moulas et al., 2014). If the
volumetric irreversible deformation of the weak zone is
considered to be negligible (see also Supporting Information Appendix S2 for details), the mean stress will be
approximately equal to the thermodynamic pressure since
the stress components within the weak zone are almost
equal (i.e., small differential stress; Figures 6d and 7). We
have therefore demonstrated, in marked contrast with
Hobbs and Ord (2017), that thermodynamic pressure, associated with low differential stress, can control metamorphic
(b)
F I G U R E 5 Mean‐stress difference (δσm) evolution in the layer during compression (a) and relaxation after compression has ceased (b) for
the model configuration displayed in Figure 2. The parameter δσm is the mean stress at the centre of the layer minus the mean stress of the
matrix at the top of the model. The lithostatic pressure (PL) within the layer has been subtracted and the result has been normalized to the layer
far‐field stress (2(μl − μm) ɛ_ b ). Time has been normalized using the characteristic Maxwell time of each material (Equation 15). A simple scaling
relationship is also shown with a solid line for reference. Time in (b) is shifted, so that t = 0 coincides with the termination of compression
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|
ET AL.
(a)
(b)
(c)
(d)
9
F I G U R E 6 (a) Tectonic overpressure (P0) calculated from the data of Schmalholz and Podladchikov (2013) for the case of continental
shortening. The lithostatic pressure is PL and PMoho is the initial (lithostatic) pressure at the Moho before compression starts. Variations of P0
indicate variations of mean stress (σm) from the lithostatic (PL). (b) Differential stress calculated from the data of Schmalholz and Podladchikov
(2013). The differential stress has been normalized by PMoho. (c) Pressure of a weak viscous elliptical inclusion subjected to far‐field stress (τff).
Pressure has been normalized to the far‐field stress of the strong surrounding rocks (for details see Moulas et al., 2014). (d) Mohr diagram for
the weak elliptical inclusion shown in (c). For the calculation of the Mohr diagram, stress is taken positive in compression. Note that the weak
elliptical inclusion has a homogenous state of stress (constant mean stress) that is represented by the small red circle. The dashed circle
corresponds to the state of stress of the matrix at the location indicated by a red dot in (c), which is at the contact with the inclusion. The far‐
field stress is indicated by a solid black circle. The mean stress of the far‐field has been subtracted from the solution, hence the circle is centred
at 0. For details on the analytical solution, refer to Schmid and Podladchikov (2003)
reactions during dissipative deformation. Such a situation is
not restricted to the large scale and to viscous rheology as
demonstrated by models of plastic extrusion and elastoplastic pressure vessels (e.g., Mancktelow, 2008; Tajčmanová
et al., 2014).
6
| DISCUSSION
We have presented theoretical arguments based on calculus
and thermodynamics in an attempt to clarify
misconceptions regarding the definition of thermodynamic
pressure from internal energy in dissipative systems. The
thermodynamic pressure is a state function and can therefore be independent of the type of process affecting a system, in contrast to the assertions of Hobbs and Ord (2017)
for the opposite. Additionally, we have presented arguments regarding the use of equilibrium thermodynamic
relations (such as EOS) in dynamic processes according to
theories coming from nonequilibrium thermodynamics.
Having a dissipative system far from equilibrium does not
mean that equilibrium thermodynamic relations do not
10
|
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ET AL.
F I G U R E 7 Mean stress (σm) in a viscous layer containing three weak viscous inclusions. The model configuration is as in Figure 2, the
main difference being the addition of these weak inclusions that have different aspect ratios and orientations. Two of the inclusions (left and
right) have an aspect ratio of 2 while the one in the centre is circular. The left inclusion has a long axis parallel to the layer. The inclusion in the
right has a long axis perpendicular to the layer. The viscosity of the inclusions and the matrix is 1019 Pa·s and the viscosity of the layer is 1021
Pa·s. The far‐field bulk‐shortening rate is 10−13 s−1. The bulk modulus of the materials is 50 GPa. The governing equations are given in
Supporting Information Appendix S1. (a) Mean‐stress (σm) distribution at the end of the simulation. (b) Mean‐stress (σm) evolution in the layer
and within the weak inclusions. (c) Differential stress (σd) evolution in the layer and the inclusions. The weak circular inclusion (labelled with
black square) yields a similar mean stress as the strong layer (labelled with magenta circle, b), but the differential stress in the inclusion is
negligible compared to the differential stress in the layer (c)
hold. Simple examples to demonstrate this point is the
modelling of chemical/thermal diffusion processes where
entropy production and dissipation are nonzero even if the
studied thermodynamic variables do not evolve with time.
If the definition of thermodynamic pressure was restricted
to isentropic processes only, as Hobbs and Ord (2017) have
proposed, then EOS would not be applicable to natural processes and therefore any relation of thermodynamic pressure to depth would be invalid.
Geodynamic models often assume that geomaterials are
incompressible. This simplification is commonly used in
models where mean stress is calculated using the lithostatic
approximation (Equation 2) or in models where the viscous
deformation of rocks is considered. We have demonstrated
that for conventional systems (Figures 1 and 4) thermodynamic pressure, calculated from compressible models, is
essentially identical to the mean stress that is calculated
from corresponding incompressible models; apart from an
initial transient period which is controlled by the Maxwell
relaxation time, tM. This was found to be the case for either
static or viscously deforming rocks. In deforming materials
with variable density and topography however, the mean
stress will deviate from the lithostatic pressure. Here, the
compressibility of the deforming materials will have an
effect on the time needed for these mean‐stress deviations
to develop (Figure 4). In the example shown, the time for
the mean‐stress buildup/relaxation is proportional to the
characteristic Maxwell time defined in Equation 15 and its
duration is about five times the Maxwell time (Figure 5).
For typical lithospheric viscosities and bulk moduli (1021
Pa·s and 40 GPa, respectively), this stress buildup lasts
almost 4 kyr. To resolve this, stress buildup in typical
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numerical geodynamic models would require time steps in
the order of a few hundred years. Such small time steps
are, however, infeasible for most current models, since it
would require more than 10,000 time steps to simulate a
deformation process lasting longer than 10 Ma. Our results
suggest that the incompressible approximation provides reasonable estimates for the mean stress in viscous geological
materials with elastic volume changes, which deform for
times longer than a few thousands of years, and can be far
more accurate than simple lithostatic approximations.
Although the link between mean stress and thermodynamic pressure is not clear when differential stresses are
high, the mean stress that develops in systems with small
differential stress will be almost equal to the thermodynamic pressure, if irreversible bulk deformation is negligible. For specific geodynamic situations, rocks with small
differential stress can have a mean stress significantly different from the lithostatic. Examples are mechanically weak
shear zones on all geological scales, which form in stressed
regimes, or weak inclusions inside stressed rocks with
higher differential stress. For such weak rocks, the phase
equilibria will record the actual mean stress and not necessarily the lithostatic pressure.
7
|
ET AL.
| CONCLUSIONS
The recent challenging of the relation between mean stress,
that evolves in space and time as it is calculated by geodynamic models, and thermodynamic pressure, used in conventional metamorphic phase equilibria, would have, if true,
severe implications for the foundations of metamorphic
petrology. Indeed, if thermodynamic pressure could not be
“usefully defined” in deforming rocks, then the majority of
thermodynamic calculations could not be performed for any
geodynamic setting, ranging from collisional orogenic belts
to divergent plate margins. Similarly, thermodynamic calculations could not be applied to heat conducting, hence dissipating rock either in the lithosphere or in the convecting
mantle/core until the complete cooling of the earth.
Here, we have clarified that the definition of thermodynamic pressure does not depend on any constraint concerning variations in entropy since it is a state function.
Therefore, the thermodynamic pressure is well defined for
processes exhibiting entropy variations with time and for
dissipative processes. Hence, lines of argumentation supporting the view of thermodynamic pressure being only
defined for isentropic processes are incorrect.
The mean stress in a deforming incompressible viscous
material is essentially identical to the mean stress in a
deforming elastically compressible viscous material, if the
irreversible volumetric deformation is negligible, and if the
deformation time is approximately five times longer than
11
the Maxwell time. For typical lithospheric rocks, this deformation time is smaller than ten thousand years. Therefore,
the mean stress calculated during numerical simulations of
long‐term (>10 kyr) geodynamic processes, which assume
incompressible deformation, provides accurate mean stress
estimates.
Stress relaxation towards lithostatic pressure does not
only require the consideration of time‐scales that are five
times longer than the Maxwell time, but it also requires the
absence of all causes for the nonhydrostatic stress state.
Causes for such nonhydrostatic stress state can be lateral
variations of topography and of crustal thickness that may
take billions of years to disappear. Moreover, the nonhydrostatic stress state is maintained as long as far‐field tectonic
stresses are present, which can be significantly longer than a
few ten thousand years. Consequently, conventional metamorphic systems under low differential stress may experience thermodynamic pressure significantly different from the
lithostatic pressure over geological time‐scales. Such thermodynamic pressure is well approximated by the mean stress,
which can be calculated with common geodynamic models.
ACKNOWLEDGEMENTS
We acknowledge the participants of the workshop “Interplay between mineral reactions and deformation” (September 2017 – ETH Zurich) for the stimulating discussions
that motivated us to write this manuscript. E.M. S.M.S.,
Y.P., and L.B. acknowledge the University of Lausanne for
financial support. L.T. acknowledges the ERC starting
grant (335577). Constructive reviews by Ross Angel &
John Wheeler, comments of an anonymous reviewer, and
editorial handling by D. Robinson are greatly appreciated.
ORCID
Evangelos Moulas
http://orcid.org/0000-0002-2783-4633
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SUPPORTING INFORMATION
Additional supporting information may be found online in
the Supporting Information section at the end of the article.
Appendix S1. Model formulation for isothermal compressible viscous deformation.
Appendix S2. Mean stress and thermodynamic pressure
for materials with dissipative volumetric deformation.
How to cite this article: Moulas E, Schmalholz
SM, Podladchikov Y, Tajčmanová L, Kostopoulos
D, Baumgartner L. Relation between mean stress,
thermodynamic, and lithostatic pressure. J
Metamorph Geol. 2018;00:1–14. https://doi.org/
10.1111/jmg.12446
APPENDIX 1
CLASSICAL IRREVERSIBLE
THERMODYNAMICS AND ENTROPY
EVOLUTION
The purpose of Appendix 1 is to show the difference
between entropy production and entropy change in time.
This difference becomes important when isentropic processes are considered. We would first like to refer to some
basic principles from what is known in the literature as
classical irreversible thermodynamics (CIT, e.g., De Groot
& Mazur, 1984; Lebon et al., 2008; Müller & Müller,
2009). CIT is based on principles that allow the use of
local thermodynamic equilibrium in dissipative systems.
Dissipative systems are those where mechanical or other
forms of energy (e.g., chemical) dissipate due to irreversible processes (e.g., Thompson, 1852). Irreversible processes produce entropy and therefore, dissipation is
associated with entropy production. The framework of CIT
combines fundamental physical laws (conservation of mass,
momentum, energy, etc.) and respects that the entropy production for every irreversible process must be greater than
zero. The entropy production is not to be confused with
entropy change in space or time. The evolution of entropy
is given by a partial differential equation of the form (e.g.,
De Groot & Mazur, 1984, their eq. 10):
14
|
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@ρs
¼
@t
@Jis;tot
þ Qs
@xi
APPENDIX 2
(1.1)
where ρ is density, s is the mass‐specific entropy (in J
K−1 kg−1), Jis;tot is the total entropy flux in the ith direction
and Qs is the entropy production (repeated indices imply
summation). This equation can be envisaged as the definition of the entropy production, Qs. According to CIT (c.f.
De Groot & Mazur, 1984, their eq. 11):
Qs ≥ 0
ET AL.
(1.2)
where the equality holds only if all the processes that operate in the system are reversible. Note that entropy production is positive for every irreversible process, so that the
entropy production of one irreversible process cannot
reduce the entropy production of another irreversible process. This CIT principle “is valid for all systems, regardless of the boundary conditions” (e.g., Kondepudi &
Prigogine, 1998, p. 336). However, entropy in nature varies with time. For example, entropy decreases in a glass of
water that is cooling and freezing in the fridge. Inspection
of Equation 1.1 in that case reveals that in order to
decrease entropy in a given volume, the divergence of the
total flux of entropy must be larger than the production
term.
A common misconception in the literature is that the
entropy production term (Qs) is confused with entropy
variation with time (see for example Hobbs & Ord,
2017; their eq. 7). This misconception can be demonstrated if we consider a stationary state (where the time
derivative of entropy is zero) for heat production in the
Earth. Setting the time derivative of Equation 1.1 to zero
reveals that the divergence of the entropic flux must
compensate for the entropy production. Therefore, even
in the case where locally, entropy does not change with
time (time derivative is zero), local entropy production
may still exist and thermodynamic relationships are still
valid in that locality according to CIT. Consequently,
statements like the one given by Hobbs and Ord (2017)
that “two or more dissipative processes balance with
respect to dissipation” or “all dissipation stops when
T s_ ¼ 0” disagree with the definition of the entropy production (Qs).
THERMODYNAMIC RELATIONS
INVOLVING HELMHOLTZ FREE ENERGY
The purpose of Appendix 2 is to show how pressure can
be related to the changes of Helmholtz free energy at constant temperature (T). Given the internal energy (U) and
the Helmholtz free energy (F) of a homogeneous elastic
body (both in J), the total stresses can be calculated from:
1 @F
1 @U
σ ij ¼
¼
(2.1)
V @ɛij T;M k V @ɛij S;M k
where V (m3) is volume, Mk (kg) is the total mass of component k, σij (Pa) are the total stress tensor components and
ɛij (dimensionless) are the strain components for small
deformations. In that case, the internal energy variation can
be written as (e.g., Landau & Lifshitz, 1986, pp. 8–9):
dU ¼ TdS þ Vσ ij dɛij þ ∑ck¼1 μk dMk
(2.2)
and the corresponding Helmholtz free energy variation can
be expressed as:
dF ¼
SdT þ Vσ ij dɛij þ ∑ck¼1 μk dMk
(2.3)
For a purely volumetric deformation, the volumetric
strain components are related to volume changes by
dV=V ¼ dεii and the stress components are related to the
thermodynamic pressure by σij = − Pδij, so that finally Vσij
dɛij = −PdV (Einstein's summation rule on repeated indices
apply and δij is Kronecker's delta, i.e., it is equal to 1 when
i = j and zero otherwise). In that case, thermodynamic
pressure can be obtained by partial differentiation of Helmholtz energy (at constant temperature):
@F
P¼
(2.4)
@V T;Mk
Although temperature is kept constant during partial differentiation, pressure is still defined if temperature varies
with time. The corresponding Helmholtz free energy variation is:
dF ¼
SdT
PdV þ ∑ck¼1 μk dMk
(2.5)
APPENDIX S1
MODEL FORMULATION FOR ISOTHERMAL COMPRESSIBLE VISCOUS
DEFORMATION
Here we present the set of equations that were used in order to obtain the two-dimensional stress
field the results of which are shown in Figures 3-5 and 7. In order to calculate stresses and velocity,
we solved the equations of momentum and mass balance assuming plane strain. The equation of
mass balance for one phase is:
�
+
�
��
=
�
(S1.1)
where � is the ith coordinate, � is time, � is density and � is the velocity component in the ith
direction (repeated indices imply summation). In the absence of inertial forces, the conservation of
linear momentum becomes:
�
− �� =
�
(S1.2)
Where � are the total stress tensor components and � is the acceleration of gravity in the jth
direction. The stress tensor � is symmetric as required by the conservation of angular momentum.
Total stress (� ) can be decomposed as:
� = −�� � + � ˙′
(S1.3)
where � is the shear viscosity of the material and �� is the mean stress taken as positive in
compression. The mean stress is obtained by:
�
�� = −
The strain rate deviator ( ˙′ ) is given by:
�
�
+
�
�
˙′ =
−
�
�
�
(S1.4)
(S1.5)
Mean stress and volumetric deformation are related via an EOS of the form:
��� = ��
��
�
(S1.6)
where �� is the isothermal bulk modulus and assuming that the material is isotropic.
Differential stress is given by the formula
� = √
�
−�
2
1
+ �2
(S1.7)
This closed system of equations was solved using an iterative finite difference approach (c.f.
Chorin, 1997; Poliakov, Cundall, Podladchikov, & Lyakhovskii, 1993) and employing a regular,
staggered-grid discretization (Virieux, 1986). Since we are considering only small deformations, we
did not consider advection.
APPENDIX S2
MEAN STRESS AND THERMODYNAMIC PRESSURE FOR MATERIALS WITH
DISSIPATIVE VOLUMETRIC DEFORMATION
In this section we show the influence of bulk viscosity, on mean stress and pressure calculations.
We consider isotropic materials for simplicity. We would like to emphasise that different
mechanical models (Maxwell, Kelvin etc) have different results with respect to the calculated
values for mean stress and therefore we give the two most basic models below.
When materials experience irreversible volumetric deformation (e.g. viscous compaction) mean
stress (�� ) is not generally equal to the thermodynamic pressure (�). A common relation that is
given for fluids is (e.g. Batchelor, 1967, p. 154):
�� = � + �� = −�� − � ̇
(S2.1)
where � is the bulk viscosity (in Pa·s) and the material is assumed to be isotropic. In this
formulation mean stress is decomposed into two parts, one is the thermodynamic pressure � (also
termed equilibrium pressure; Batchelor, 1967, p. 154) and the other is a pressure that results from
viscous volumetric deformation �� (e.g. Müller & Müller, 2009, p. 344). When we consider an
elastic isotropic material with negligible bulk viscosity then �� reduces to � (as shown also in
Appendix 2). This formulation (Equation S2.1) is a Kelvin-type model for viscoelastic volumetric
deformation, which means that both bulk deformations are arranged in parallel. For such parallel
arrangement the volumetric strain and strain rate is equal for viscous and elastic bulk deformation,
however, the corresponding pressures are different. Similar formulations can be obtained if the
plastic volumetric deformation is considered, however, these terms are usually assumed to be
negligible.
An alternative formulation for viscoelastic irreversible deformation is the Maxwell model in which
the volumetric strains are arranged in series. For this arrangement, both pressures are identical, �� =
�, but the corresponding volumetric strain and strain rates are different. In such a model the
volumetric deformation rate is the sum of viscous and elastic deformation as shown below
�� �̇
(S2.2)
̇ = ̇� + ̇ = − −
� ��
However, we note that under constant load this model would constantly creep and, for example, the
volume of any material under the influence of gravity would eventually reduce to zero. Evidently,
this is not the case and this is the reason why a simple Maxwell model is not used to describe large
volumetric deformations. Following a similar logic, plastic dilatational deformation must also
become negligible when rocks are under high confining pressure and when they experience a few
percent strain (e.g. Vermeer & de Borst, 1984, pp. 14–15).
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