United States presidential election in Montana, 1996

Main article: United States presidential election, 1996

United States presidential election in Montana, 1996

November 5, 1996 (1996-11-05)

Nominee Bob Dole Bill Clinton Ross Perot Party Republican Democratic Reform Home state Kansas Arkansas Texas Running mate Jack Kemp Al Gore Patrick Choate Electoral vote 3 0 0 Popular vote 179,652 167,922 55,229 Percentage 44.11% 41.23% 13.56%

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President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

The 1996 United States presidential election in Montana took place on November 5, 1996. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana voted for Senate Majority Leader Bob Dole over President Bill Clinton by a slim margin of 2.88%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 13.56% of the popular vote in Montana.

Results

United States presidential election in Montana, 1996
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Republican	Bob Dole	Jack Kemp	179,652	44.11%	3
	Democratic	Bill Clinton	Al Gore	167,922	41.23%	0
	Reform	Ross Perot	Patrick Choate	55,229	13.56%	0
	Libertarian	Harry Browne	Jo Jorgensen	2,526	0.62%	0
	Natural Law (write in)	John Hagelin	Mike Tompkins	1,754	0.43%	0
	Constitutional (write in)	Howard Phillips	Herbert Titus	152	0.04%	0
	(write in)	Charles E. Collins	Rosemary Giumarra	20	0.00%	0
	Independent (write in)	Write-ins		5	0.00	0
	Socialist (write in)	Mary Cal Hollis	Eric Chester	1	0.00	0