United States presidential election in Rhode Island, 1920
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The 1920 United States Presidential Election in Rhode Island took place on November 2, 1920 as part of the 1920 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for Republican nominee, Senator Warren G. Harding of Ohio, over the Democratic nominee, Governor James M. Cox of Ohio. Harding ran with Governor Calvin Coolidge of Massachusetts, while Cox ran with Assistant Secretary of the Navy Franklin D. Roosevelt of New York.
Harding won Rhode Island by a margin of 31.19%. His victory in the New England states was helped in by the local popularity of his running mate, Calvin Coolidge, a traditional New England Yankee born in the small-town of Plymouth Notch, Vermont, who had started his political career nearby as Governor of Massachusetts.
Results
United States presidential election in Rhode Island, 1920[1] | ||||||||
---|---|---|---|---|---|---|---|---|
Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Warren Gamaliel Harding of Ohio | Calvin Coolidge of Massachusetts | 107,463 | 63.97% | 5 | 100.00% | ||
Democratic | James Middleton Cox of Ohio | Franklin Delano Roosevelt of New York | 55,062 | 32.78% | 0 | 0.00% | ||
Socialist | Eugene Victor Debs of Indiana | Seymour Stedman of Illinois | 4,351 | 2.59% | 0 | 0.00% | ||
Prohibition | Aaron Sherman Watkins of Indiana | David Leigh Colvin of New York | 510 | 0.30% | 0 | 0.00% | ||
Socialist Labor | William Wesley Cox of Missouri | August Gillhaus of New York | 495 | 0.29% | 0 | 0.00% | ||
style="background-color: {{Template:Single Tax/meta/color}}; width: 5px;" | | [[Single Tax|{{Template:Single Tax/meta/shortname}}]] | Robert Colvin Macauley of Pennsylvania | Richard C. Barnum of Ohio | 100 | 0.06% | 0 | 0.00% | |
Total | 167,981 | 100.00% | 5 | 100.00% |
References
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