is_int

(PHP 4, PHP 5, PHP 7, PHP 8)

is_int — Verifica se una variabile è di tipo integer

Descrizione

is_int(mixed $var): bool

Verifica se una variabile è di tipo integer.

Nota:
Per testare se una variabile è un numero o una stringa numerica (come negli input dei form, che sono sempre una stringa), bisogna usare is_numeric().

Elenco dei parametri

var: La variabile da valutare.

Valori restituiti

Restituisce true se var è un integer, false in caso contrario.

Esempi

Example #1 Esempio di is_int()

<?php
$values = array(23, "23", 23.5, "23.5", null, true, false);
foreach ($values as $value) {
    echo "is_int(";
    var_export($value);
    echo ") = ";
    var_dump(is_int($value));
}
?>

Il precedente esempio visualizzerà:

is_int(23) = bool(true)
is_int('23') = bool(false)
is_int(23.5) = bool(false)
is_int('23.5') = bool(false)
is_int(NULL) = bool(false)
is_int(true) = bool(false)
is_int(false) = bool(false)

Vedere anche:

is_bool() - Verifica se una variabile è di tipo boolean
is_float() - Verifica se una variabile è di tipo float (decimale a virgola mobile)
is_numeric() - Verifica se una variabile è un numero o una stringa numerica
is_string() - Verifica se il tipo di una variabile sia stringa
is_array() - Verifica se una variabile è un array
is_object() - Verifica se una variabile è un object

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User Contributed Notes 11 notes

down

167

Simon Neaves ¶

16 years ago

I've found that both that is_int and ctype_digit don't behave quite as I'd expect, so I made a simple function called isInteger which does. I hope somebody finds it useful.

<?php
function isInteger($input){
    return(ctype_digit(strval($input)));
}

var_dump(is_int(23)); //bool(true)
var_dump(is_int("23")); //bool(false)
var_dump(is_int(23.5)); //bool(false)
var_dump(is_int(NULL)); //bool(false)
var_dump(is_int("")); //bool(false)

var_dump(ctype_digit(23)); //bool(true)
var_dump(ctype_digit("23")); //bool(false)
var_dump(ctype_digit(23.5)); //bool(false)
var_dump(ctype_digit(NULL)); //bool(false)
var_dump(ctype_digit("")); //bool(true)

var_dump(isInteger(23)); //bool(true)
var_dump(isInteger("23")); //bool(true)
var_dump(isInteger(23.5)); //bool(false)
var_dump(isInteger(NULL)); //bool(false)
var_dump(isInteger("")); //bool(false)
?>

down

Robin ¶

14 years ago

Keep in mind that is_int() operates in signed fashion, not unsigned, and is limited to the word size of the environment php is running in.

In a 32-bit environment:

<?php
is_int( 2147483647 );           // true
is_int( 2147483648 );           // false
is_int( 9223372036854775807 );  // false
is_int( 9223372036854775808 );  // false
?>

In a 64-bit environment:

<?php
is_int( 2147483647 );           // true
is_int( 2147483648 );           // true
is_int( 9223372036854775807 );  // true
is_int( 9223372036854775808 );  // false
?>

If you find yourself deployed in a 32-bit environment where you are required to deal with numeric confirmation of integers (and integers only) potentially breaching the 32-bit span, you can combine is_int() with is_float() to guarantee a cover of the full, signed 64-bit span:

<?php
$small = 2147483647;         // will always be true for is_int(), but never for is_float()
$big = 9223372036854775807;  // will only be true for is_int() in a 64-bit environment

if( is_int($small) || is_float($small) );  // passes in a 32-bit environment
if( is_int($big) || is_float($big) );      // passes in a 32-bit environment
?>

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e dot sand at elisand dot com ¶

15 years ago

Simon Neaves was close on explaining why his function is perfect choice for testing for an int (as possibly most people would need).  He made some errors on his ctype_digit() output though - possibly a typo, or maybe a bug in his version of PHP at the time.



The correct output for parts of his examples should be:



<?php

var_dump(ctype_digit(23)); //bool(false)

var_dump(ctype_digit("23")); //bool(true)

var_dump(ctype_digit(23.5)); //bool(false)

var_dump(ctype_digit(NULL)); //bool(false)

var_dump(ctype_digit("")); //bool(false)

?>



As you can see, the reason why using *just* ctype_digit() may not always work is because it only returns TRUE when given a string as input - given a number value and it returns FALSE (which may be unexpected).

down

andre dot roesti at 7flex dot net ¶

14 years ago

With this function you can check if every of multiple variables are int. This is a little more comfortable than writing 'is_int' for every variable you've got.

<?php
function are_int ( ) {
    $args = func_get_args ();
    foreach ( $args as $arg )
        if ( ! is_int ( $arg ) )
            return false;
    return true;
}

// Example:
are_int ( 4, 9 ); // true
are_int ( 22, 08, 'foo' ); // false
?>

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Hector (hector-ordonez.com) ¶

8 years ago

Simon Neaves's answer is incomplete: negative integers will return false.

I recommend checking stackoverflow's answers:
http://stackoverflow.com/questions/6416763/checking-if-a-variable-is-an-integer-in-php

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davide dot renzi at gmail dot com ¶

8 years ago

I've found a faster way of determining an integer.
On my env, this method takes about half the time of using is_int(). 

Cast the value then check if it is identical to the original. 

<?php 
if ( (int) $n !== $n ) { 
    echo 'not is int'; 
} else { 
    echo 'is int'; 
} 
?>

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petepostma at gmail dot spam dot com ¶

12 years ago

There is a versa to the vice of this int only type check.

is_int( $integer_type) will only return true, if the TYPE is int, not the value
ctype_digit( $string_type) will only return true if the TYPE is string, and its value is INT

therefore:
 return ( is_int($value) || ctype_digit($value) );

down

nicolas dot giraud at actiane dot com ¶

12 years ago

Just a shorter way to check if your variable is an int or a string containing a int without others digit than 0 to 9 :

<?php 
$bool = ( !is_int($value) ? (ctype_digit($value)) : true );

$value = 42; //true
$value = '42'; //true
$value = '1e9'; //false
$value = '0155'; //true
$value = 0155; //true
$value = 0xFF; //true while it's just the same as 255
$value = '0xFF'; //false
$value = 'a'; //false
$value = array(); //false
$value = array('5'); //false
$value = array(5); false
$value = ''; //false
$value = NULL; //false

?>

Short & cool :)

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Vasiliy Makogon ¶

8 years ago

If you want detect integer of float values, which presents as pure int or float, and presents as string values, use this functions:

<?php 
function isInteger($val)
{
    if (!is_scalar($val) || is_bool($val)) {
        return false;
    }
    if (is_float($val + 0) && ($val + 0) > PHP_INT_MAX) {
        return false;
    }
    return is_float($val) ? false : preg_match('~^((:?+|-)?[0-9]+)$~', $val);
}

function isFloat($val)
{
    if (!is_scalar($val)) {
        return false;
    }
    return is_float($val + 0);
}

foreach ([
    '11111111111111111', 11111111111111111, // > PHP_INT_MAX - presents in PHP as float 
    1, '10', '+1', '1.1', 1.1, .2, 2., '.2', '2.', 
    '-2.', '-.2', null, [], true, false, 'string'
] as $value) {
    echo $value . ':' . gettype($value) . ' is Integer? - '  . (isInteger($value) ? 'yes' : 'no') . PHP_EOL;
    echo $value . ':' . gettype($value) . ' is Float? - '  . (isFloat($value) ? 'yes' : 'no') . PHP_EOL;
}
?>

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me at rexxars dot com ¶

15 years ago

I was looking for the fastest way to check for an unsigned integer which supported large numbers like 4318943448871348 or 0xFFFFFFFF.

Fastest I came up with is this:
<?php
function is_unsigned_int($val) {
    return ctype_digit((string) $value));
}
?>

Will return true on 1515, 0xFFFFFFFF, '3515' and '1365158185855141'.
Will return false on 0.1515, '415.4134' and '-616'.

Be aware though, before PHP 5.1.0 this will return true on an empty string.

According to my benchmarks this is about 30% faster than the regex ^\d+$.

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gabe at websaviour dot com ¶

21 years ago

Although this can be inferred from the documentation, beware of numeric strings.  I ran into the problem in a MySQL app where I would either SELECT an INT PRIMARY KEY or INSERT a new record and use mysql_insert_id() to get the KEY before continuing onto the new section.  

I used is_int() to make sure the subsequent queries wouldn't break when using the key variable.  Unfortunately I failed to realize that while mysql_insert_id() returns an int, mysql_result() always returns a string even if you are SELECTing from an INT field.

Spent at least 30 minutes trying to figure out why existing records weren't getting linked, but new records would link fine.  I ended up using intval() on mysql_result() to make sure subsequent queries still always work.

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